http://en.wikipedia.org/wiki/Damerau%E2%80%93Levenshtein_distance
On Tue, May 22, 2012 at 7:06 PM, aanchal goyal goyal.aanch...@gmail.comwrote:
@Lucifer, do we need to add insert and del operations in the
transformation formula u gave? Isn't it just the number of substitutions/2?
--
You
Will fail for the sing having say 257characters all same
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Sat, May 26, 2012 at 12:26 PM, Navin Gupta navin.nit...@gmail.comwrote:
This is called Run-Length-Encoding (RLE) of a string.
Its purpose
Another approach is to form a singly linked, NULL-terminated list
(connected e.g. by 'left' pointers). This is a harder problem, and
it
might be required if you have a purpose for the other (right)
pointer. If you need a doubly linked list it's easy to walk down the
singly linked one, creating
@Gene :
NODE *convert(NODE *root, NODE *list)
{
if (root == NULL) return list;
NODE *left_subtree = root-left;
root-left = convert(root-right, list);
return *tree(left_subtree, root);*
}
what *tree(left_subtree, root)* function doing here??
On Sun, May 27, 2012 at 7:12 PM, Gene
@jalaj :- we will be sorting a copy of the word and then matching the
sorted_sequence with the sorted_sequence of the copy of other words.
It will still be in-place, because we are using a space of Word size where
the input is a dictionary.
This is an amortized in-place.
--
Navin Kumar Gupta
@atul:
if i have understood ..
ur solution will break when the string has repeated characters.
e.g. for baa
On Tue, May 22, 2012 at 3:43 PM, partha sarathi Mohanty
partha.mohanty2...@gmail.com wrote:
sorry it was treeset Here is the code..
public class asd1 {
public static
@saurabh : i kinda assumed that string will not contain repeated character.
reason being if string has repeated character , say in your case baa then
baa will be repeated
twice hence it would be difficult to justify the output for this input
answer could be say 2 or 3 or both are correct.
On
complex_number const operator =(complex_number temp) const
{
return *this;
}
what is the job of marked 'const'???
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@atul:
i dont agree that baa should come once or twice is arguable.
It definitely have to be one time only..
we are supposed to get all lexicographic combinations (which implicitly
means no two strings will be same..)
On Mon, May 28, 2012 at 12:23 AM, atul anand atul.87fri...@gmail.comwrote:
const allows this function to be called on constant object.
So if someone creates an const obj of this class. Assignments can be done.
On Mon, May 28, 2012 at 12:23 AM, amrit harry dabbcomput...@gmail.comwrote:
complex_number const operator =(complex_number temp) const
{
return
Its a const member function, you cant return reference to the object.
Const member function never allows you to modify the data until unless its
a mutable. So here we are passing the reference to object which is
modifiable, it conflicts with the const member function property.
So the compiler
Yes, navin thats a good solution...
... we dont need to work on the whole array but of size k x k (k rows and
k columsn only). Rest of the array we can simply ignore..
complexity of youngify is O(k) for every removing every element.
we have to remove k-1 elements so complexity of whole
@amrit
Every non-static member function of a class has an implicit parameter
that is passed to the function (when called) This implicit parameter
is nothing but the this pointer. Now if you want to make the
implicit parameter (this pointer) a const, how would u do it? This
is done by placing the
1) Linearize the DAG using DFS. ( topological sorting)
2) Now take an array of size A[N] ( N - nodes in the DAG ), where A[i]
mimics the 'i'th node in the linearized list.
3) Scan the linearized list from left to right to get to the source
node and initialize all the corresponding values in array
the job of marked const here is to make the member function operator= as
const so it can't modify any member function values unless that member
function is mutable
@manikanta
the compiler will throw an error only when we try to modify any members
inside a const member function but here we are not
@Bhaskar u r right. I mean wen u are trying to access this function on non
constant object.
On May 28, 2012 2:08 AM, Bhaskar Kushwaha bhaskar.kushwaha2...@gmail.com
wrote:
the job of marked const here is to make the member function operator= as
const so it can't modify any member function
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