after few attempts I think you must be getting stuck where you need a^3 +
b^3 + c^3 value in terms of abc, C1, and C2 which is possible using this
identity--
(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)-abc]
refer this link for the proof
http://math.stackexchange.com/questions/288965/show-that-abc-a-b
If a+b+c=C1 and ab+bc+ac=C2, how do you get abc?
C1,C2 are constant.
--
regards,
soumya prasad ukil
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to algogee
Iterate through index_name, for each value you traverse, now try to find
inside name_age by calling find on it. Now if it is found, put it temporary
map.
Now the iteration is over, clear index_name map. Put all the values from
temporary map into _name map.
On 9 May 2013 21:40, Nishant Pandey wr
