thanks for the code.....
On Wednesday, July 25, 2012 7:29:36 PM UTC+5:30, Navin Kumar wrote:
>
> logic is very simple ...just trace the program you will understand.
>
> On Wed, Jul 25, 2012 at 7:28 PM, Navin Kumar <algorithm.i...@gmail.com>wrote:
>
>> #include <stdio.h>
>> #include <stdlib.h>
>> #include <ctype.h>
>>
>> char *decrypt(char *s)
>> {
>> int n;
>> char *digit = (char *)malloc(sizeof(char) * 5);
>> char *p1 = (char *)malloc(sizeof(char) * 1024);
>> char *p = p1;
>>
>> char *digit2;
>> char prev;
>> prev = *s;
>>
>> *p++ = *s++;
>>
>> while(s != '\0') {
>> if(isdigit(*s)) {
>> digit2 = digit;
>> while(isdigit(*s))
>> *digit2++ = *s++;
>> *digit2 = '\0';
>> n = atoi(digit);
>> while(n > 1) {
>> *p++ = prev;
>> n--;
>>
>> }
>> }
>> prev = *s;
>> if(*s != '\0')
>> *p++ = *s++;
>> else{
>> *p = *s;
>> break;
>> }
>>
>>
>> }
>> *p = '\0';
>> return p1;
>> }
>>
>> int main()
>> {
>> char *s = "a10b10c1d3e4";
>> char *s2 = decrypt(s);
>>
>> printf("%s", s2);
>> return 0;
>>
>> }
>>
>> On Wed, Jul 25, 2012 at 6:46 AM, Sathish babu <satbrucei...@gmail.com>wrote:
>>
>>> can anyone provide the code to convert ab1cd3 to abcddd
>>> **~Sathish Babu~**
>>>
>>>
>>>
>>> On Tue, Jul 24, 2012 at 11:39 PM, Mind Boggler <min.b...@gmail.com>wrote:
>>>
>>>> Traditional decryption problem
>>>> Convert a3b2c5 into aaabbccccc
>>>> Can anyone Put forward an algo for the test case: a3b1c3d1
>>>> Thanx
>>>>
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>>
>>
>
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