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> *MOHIT VERMA*
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1/6*5/6*5/6*3+ 1/6*1/6*5/6*3+ 1/6*1/6*1/6 =91/216
On Sat, Aug 6, 2011 at 8:24 PM, muthu raj wrote:
> Microsoft written:
>
> What is the probability of getting atleast one 6 in 3 attempts of a dice?
>
>
> *Muthuraj R
> IV th Year , ISE
> PESIT , Bangalore*
>
>
>
>
> On Sat, Aug 6, 2011 at 7:34 A
