o the Google Groups
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http://linuxconfig.org/get-started-with-android-application-development-using-linux-and-android-sdk
this link will definitly gonna give you running HELLO ANDROID app on ua
machine.
;)
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VIKAS SINGH
MCA- final year
NIT DURGAPUR
email:
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shyguy1
On Wed, Aug 24, 2011 at 8:25 PM, praneethn wrote:
> *max=(a>b)*a+(b>a)*b;*
Not allowed ;) Read the constraints applied.
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email:
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I need to know, What's the Recruitment Procedure in college of CA
Technologies.. Any Link, any info.. Plz Provide it ASAP..
Thanks in Advance :)
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> --Gopi
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o compile this
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MCA- final year
NIT DURGAPUR
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vikas.singh1...@gmail.com
shyguy1...@gmail.com
http://smrit.wordpress.com
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gorithm Geeks" group.
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dev c++.. i m getting correct out put as 24.
> when i hav executed ur code on turbo version it shows 11 ,i.e it is doing
> no padding at all..
> On Sat, Aug 6, 2011 at 7:21 PM, vikas singh wrote:
>
>> @sandeep
>>
>>
>> size = 16 address=3220095484
>
Thanks and Regards
VIKAS SINGH
MCA- final year
NIT DURGAPUR
email:
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struct demo
{
char c;
double d;
int s;
};
what wud be the size of struct demo object?
if you get the concept, then try this one... just one student asked this in
other thread :) :)
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MCA- final year
NIT DURGAPUR
email:
vikas.singh1
char :3;
ans =1 bytes
short u :3;
ans=2 bytes
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MCA- final year
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expect the PADDING would be.. try it..!
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shyguy1...@gmail.com
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Each game eliminates one participant 5622 will have to be eliminated, so
5622 games.
On Wed, Jan 12, 2011 at 3:09 PM, manoj lalavat wrote:
> check this...
>
> Tournament Algorithm
>
> Another method is tournament algorithm. The idea is to conduct a knockout
> minimal round tournament to decide th
I agree with the trie solution. But now how do you generalise it for K. I
mean a word can be made from k other words.
On Wed, Jan 12, 2011 at 12:53 AM, juver++ wrote:
> If you represent dictionary as a hash table, lookup costs you O(L) at
> least!
> Cause you need to calculate hash for the strin
Wouldn't that be O(n2) . what if n, ne, new, news, newsp etc all are valid
words ? Cant it be optimized?
On Tue, Jan 11, 2011 at 6:27 PM, juver++ wrote:
> Use trie (or similar DS).
> For each word, try to find second part of the target in a linear time
> O(length).
>
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please ignore earlier message...it was supposed to be a private message..
On Tue, Jan 11, 2011 at 6:52 PM, Vikas Singh wrote:
> lalla..bruteforce na bako.. :P
>
>
> On Tue, Jan 11, 2011 at 6:07 PM, manoj lalavat wrote:
>
>> you can optimize BF
>>
>> newspaper
time first word exist in
> dictionary then only see whether the word with the remaining characters
> exist in the dictionary or not.
>
>
> On Tue, Jan 11, 2011 at 5:57 PM, Vikas Singh wrote:
>
>> Given a dictionary find out if given word can be made by two words in
>> diction
Given a dictionary find out if given word can be made by two words in
dictionary. For eg. given "newspaper" you have to find if it can be made by
two words. (news and paper in this case). I cant think of anything but brute
force.
Thanks,
Vikas
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Hi all,I faced this problem in my lab exam.I wonder if there could be any other method than brute force(for finding out no.s to be swapped) is possible.We've all seen magic squares before. They are square grids full of numbers arranged so that the rows, columns and diagonals all have the same sum:
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