1> It is a very important linux utility .
2> If U simply type make on terminal , it will look for makefile in
the folder and subfolder and will execute it
3> If a program consists of several file eg :- main.c ,fun () in
fun.c , type () in type.c . Now , suppose type calls fun() , main
call both
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> http://groups.google.com/group/algogeeks?hl=en.
>
>
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*Durgesh Kumar*
Final Year, B.tech
Information Technology
HALDIA INSTITUTE OF TCHNOLOGY
HALDIA
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#include
int main()
{
int i=0;
printf("hello world \n");
i++;
fork();
printf("forking %d",i);
i++;
}
o/p :-
hello world
Can any1 explain this??
On 1/17/12, Durgesh Kumar wrote:
> How can we join after the fork
How can we join after the forking
On 1/17/12, Durgesh Kumar wrote:
> #include
>
> int main()
> {
> int i=0;
> printf("helllo world %d\n",i);
> i++;
> fork(); //Fork Exeution Starts from here .
> prin
.
>
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ABAD
>
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@dumanshu
> ok ! i got a O(n lgn) finally
> i don know exact complexity
> Let N = size of first array
> Find the first N smallest elements using one pointer in each array
> now swap the list of elements from index 0 to second-pointer in
> second array to first array
> with first_poiner+1 to N in f
@oppilas:- yes U r right... i simply mistyped it...I think evrythng else
is ok.
thanks Durgesh
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@swathi:- nice try bt could u explain for
A<1--->B<--6-->C<-3>D<--2>E
thanks
Durgesh
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sry it was mistyped
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For more options, visi
dear swathi,
i m not geetint solution for this pexample according to your algo.cold u
explain me wth this example ...
A<--1--->B<--5-->C<-3->D<2>E
thanks in advance
durgesh
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On Thu, Jul 7, 2011 at 4:15 PM, Gaurav Tyagi wrote:
> How about this ?
>
> 1. We construct a graph with these nodes.
> 2. We make an incoming edge on a node if it is created using some
> other node. Ex: 7=5+2. So 7 will have 1 incoming and 5 & 2 will have
> outgoing.
> 3. Select all the nodes whi
On Thu, Jul 7, 2011 at 6:41 PM, Swathi wrote:
> My solution,
>
> a) First sort the distances.
> b) We will consider the first 2 minimum numbers.. They are definitely the
> distances between the 3 nodes...
> c) Find the sum of the first 2 minimum numbers.. If this sum is outside "n"
> then we simp
step:-
1) sort the array
2) remove the smallest and largest element from arary. keep the smallest
elemnt in seperate queue(result)
3) repeat the above untill the array is empty or it contains only it
contains only one element
4) put the last element also in the queue (result)
eg:-for ur example
s
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