Hi Mark,
I will be available between 10 am to 4 pm tomorrow. So you can connect me
any time in between.
On Tue, 16 Jun 2020, 19:02 Pavan_DigitalTechnocryne, <
pavan.mtech1...@gmail.com> wrote:
> Hi ,
>
>
>
> I am Mark from Infinate360 Consulting Services. Recently we saw your
> linkedin profile
.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo.- 8050142693
Email
.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo.- 8050142693
Email Id- sanjiv2009...@gmail.com
--
You received this message because you
.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo.- 8050142693
Email Id- sanjiv2009...@gmail.com
--
You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
To post
u r right.
On Mon, Mar 12, 2012 at 11:17 AM, atul anand atul.87fri...@gmail.comwrote:
@sanjiv : wont work for this test case :-
{1,5,3,6,2,7,8};
On Mon, Mar 12, 2012 at 10:54 AM, sanjiv yadav sanjiv2009...@gmail.comwrote:
@atul anand- It will still work as follows
/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo.- 8050142693
Email Id- sanjiv2009...@gmail.com
--
You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from
email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo.- 8050142693
Email Id- sanjiv2009...@gmail.com
--
You received this message because you are subscribed to the Google
group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo
: p
and z.
if 2 pointers meet at some node x, different from q, in last step they
must have met at x', the predecessor of x.
the above logic holds for all nodes in cycle except q.
@ sanjiv yadav:
They will meet at the start of loop.
ex. a-b-c-d-e-c-d-e...
First round:
A: a-b-c-d
B: a-c-e
at
http://groups.google.com/group/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo.- 8050142693
Email Id- sanjiv2009...@gmail.com
--
You received this message because you are subscribed to the Google Groups
Algorithm Geeks group.
To post to this group, send email to algogeeks
s...@7fast@3
s...@4..fast@4...
they are equal..means we are at start of loop.
i got the algo...but didnt get the logichow they are meeting @start.
On Fri, Mar 9, 2012 at 7:42 PM, sanjiv yadav sanjiv2009...@gmail.comwrote:
suppose linked list is
a-b-c-d-e
and suppose loop
from this group, send email to
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
--
Regards
Sanjiv Yadav
MobNo.- 8050142693
Email Id- sanjiv2009...@gmail.com
--
You received this message because you
suppose we have to swap bits b1 and b2 in a number n.Then
if(b1==b2) do not do any thing
else take a hexadecimal number whose all bits are zero except bits b1 and
b2.bit b1=1 and bit b2=1
now xor of original no with this no will give the desired result.
On Sun, Oct 30, 2011 at 10:32 AM,
suppose we have to swap bits b1 and b2 in a number n.Then
if(b1==b2) do nothing
else take a hexadecimal number whose all bits are zero except bits b1 and
b2.bit b1=1 and bit b2=1
now xor of original no with this no will give the desired result.
On Sun, Oct 30, 2011 at 10:32 AM, shiva@Algo
suppose we have to swap bits b1 and b2 in a number n.Then
if(b1==b2) do nothing
else take a hexadecimal number whose all bits are zero except bits b1 and
b2.bit b1=1 and bit b2=1
now xor of original no with this no will give the desired result.suppose
we have to swap bits b1 and b2 in a
node sort(node root)
{
node first;
int count=0;count1=0;count2=0;
for(first=root;first !=null;first=first-next)
{
if(first-data==1) count++;
if(first-data==2) count1++;
if(first-data==3) count2++;
}
first=root;
for(first;first !=null;first=first-next)
{
if(count0)
{
first-data=1;
count--;
}
else
it is really good algorithm
On 8/2/11, Deepak giggs deepakthegi...@gmail.com wrote:
@varun : clear :) thanks...
On Mon, Aug 1, 2011 at 11:44 PM, kartik sachan
kartik.sac...@gmail.comwrote:
similar type algo is there in geeksforgeeks.org in array section from
there u can
17 matches
Mail list logo