, 2011 at 4:26 AM, atul anand atul.87fri...@gmail.com wrote:
Ignore my previous comment
On 16 Dec 2011 17:35, atul anand atul.87fri...@gmail.com wrote:
@All : can't we use Levenshtein algorithm to find min
addition/deletion.??
On Fri, Dec 16, 2011 at 2:50 PM, top coder topcode
@Lucifer
In your algo: how do we get the starting index of the subarray i.e
result?
On Jan 1, 11:03 pm, Lucifer sourabhd2...@gmail.com wrote:
@atul..
Below i have explained how the reduction from N^2 to N log N approach
will work..
Space complexity 2*N = O(N)
The following data
Suppose you have a tree. A binary tree (for something like
simplicity :p). You are traversing it (using infix, postfix or prefix)
to search for a node. You find your required node. You just realized
that you need to know the path from this node back to the root node
(and/or vice versa). Given the
Nice Solution and explanation Lucifer :)
On Dec 31, 4:48 pm, Lucifer sourabhd2...@gmail.com wrote:
@atul..
Yup.. exactly.. i think the problem is itself about narrowing the
range and works really well as each node can have only one child.. :)
On 31 Dec, 13:09, atul anand
Within a 2D space, there is a batch of points(no duplicate) in the
region (0,0),(0,1),(1,0),(1,1), try to find a line which can divide
the region to 2 parts with half points in each .the input will be an
array of points and the length of the array.
struct point{
int x;
int y;
};
input :
= mid;
}
else
break;
}
if ( i == N)
printf (YES);
else
print(NO);
On 30 Dec, 12:51, top coder topcode...@gmail.com wrote:
Input : You have been given a sequence of integers.
Now without actually constructing BST from the given sequence of
integers
Input : You have been given a sequence of integers.
Now without actually constructing BST from the given sequence of
integers (assuming the sequence is pre-order) determine if each node
of BST has single child (either left or right but not both).
Output : YES if given integer sequence
Given a long string and a given word find out how many times you can
write that word using subsets of the string. (i.e., you can create
dog with doom dogged 8 times.
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Does your algo will take of repeated elements?
In the above example
there are 2 d's and 3 o's and 2 d's and hence it is resulting in 2x2x2
= 8 times dog
On Dec 28, 3:58 pm, Lucifer sourabhd2...@gmail.com wrote:
@1..
A recursive app shall do...
@2
Isn't this problem similar to LCS problem
@Lucifer
Your solution works :)
On Dec 29, 2:41 am, Lucifer sourabhd2...@gmail.com wrote:
@topcoder
The above given algo takes care of repeated elements..
Let me know if u find a test case where its failing..
On Dec 29, 12:47 am, Tamanna Afroze afroze...@gmail.com wrote:
This is
Given an n x n grid with a person and obstacles, how would you find a
path for the person to a particular destination? The person is
permitted to move left, right, up, and down
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Hello Sid
Your code is working for N=4,8 but failing when N=9
9 is expressed as 3^2 but your code is giving output as :Not possible.
On Dec 26, 9:36 pm, sid1 siddhantkhann...@gmail.com wrote:
This algorithm won't work as primes might have different power. for
eg. N=12
12 is divisible by 2
Find the longest continuous subsequence of numbers in an unsorted
array such that difference between any two nos. in that sequence
should not be more than K.
For example:
2,1,8,12, 10,15, 13, 25 and k=7
8,12,10,15,13 is the sequence (15-8=7)
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give an algorithm to find if a given integer is of the form m^n where
m 1 and n 1
One Approach I can think of is to find prime factors and verify if
they are of the form m^n
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Hello Samm
I got your approach
It seems it is not working for some of the examples
Eg: N = 6
6 = 2X3 = 1X6 and hence it is not possible
but your code prints Yes possible.
On Dec 26, 9:03 pm, SAMMM somnath.nit...@gmail.com wrote:
From Wht I can understand from problm to check whether N can
What about the case of the numbers having same frequency?
Which one should come first?
On Dec 24, 11:18 pm, atul anand atul.87fri...@gmail.com wrote:
first sort the given array , you will get
1,1,1,1,2,2,2,3,3,3,3,3,4,4,5
now count frequency of each number and insert it into min heap.
each
Consider an array of N integers. Find the longest contiguous subarray
so that the average of its elements is greater than a given number k
I know the general brute force solution in O(N^2). Is there any
efficient solution using extra space?
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, 2 additions would
be required to convert it into a palindrome..
The possible palindromes would be:
for NIN :
N + AT + I(TA)N = NATITAN
for NAN :
N + TI+ A(IT)N = NATITAN
On Dec 15, 11:24 am, top coder topcode...@gmail.com wrote:
@Mohit
Suppose for example
String: NITAN
int LIDS ( vectorint a , int n ){
int s[51][2];
for(int i = 0 ; i n ; i++)
for(int j = 0 ; j 2 ; j++)
s[i][j] = 1;
for(int i = 0 ; i n ; i++){
for(int j = 0 ; j i ; j++){
if( a[i] != a[j] ){
s[i][a[i]a[j]] =
Given a word, convert it into a palindrome with minimum addition of
letters to it. letters can be added anywhere in the word.
. for eg if hello is given, result should be hellolleh
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:
Find the LCS of string with its reverse
On Wed, Dec 14, 2011 at 8:33 PM, top coder topcode...@gmail.com wrote:
Given a word, convert it into a palindrome with minimum addition of
letters to it. letters can be added anywhere in the word.
. for eg if hello is given, result should
();
if(val == str[i])
{
i++;
}
}
if(isDequeueEmpty())
{
//we know that from start to i is a repeated substr and should be
removed.
}
On Mon, Dec 12, 2011 at 7:52 PM, top coder topcode...@gmail.com wrote:
For example if aabbabc is given as input after first
If pairwise sums of 'n' numbers are given in non-decreasing order
identify the individual numbers. If the sum is corrupted print -1
Example:
i/p:
4
4 5 7 10 12 13
o/p:
1 3 4 9
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