Ans should be 45km/hr. :)
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UDIT
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6,24,60,120,210,336..
(N^3 - N) where N=2,3,4
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UDIT
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93747..
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UDIT
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For
Q-8: 50,25,10,10,10,10
Q2-: Let A,B,C and D are the persons suct tat A takes 1min, B-2, C-5 and
D-10
* A and B go across 2 minutes
A goes back with light 1 minute
C and D go across 10 minutes
B goes back with light 2 minute
A and
Its Ceiling of (n/2) In both cases atmost comparisons will be 3
* Ceiling of (n/2)...
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If n is odd, then we perform
3*n/2 comparisons. If n is even, we perform 1 + 3*(n-2)/2
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@Vaibhav: Sunny is also right bcz if u jst copy n paste d above code with (/
*jp) it'll show an error... And the error is in printf statement. jst cut it
from the program n thn write it again.. It'll wrk properly
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I think this is also a compiler dependent program..
Bcz if u run d code
#includestdio.h
typedef struct
{
char *name;
double salary;
}job;
main()
{
static job a={tcs,15000.0};
static job a={ibm,25000.0};
static job a={google,35000.0};
int x=5;
job *arr[3]={a,b,c};
Since the product of their ages is 36. So the possible combination of ages
may b: either
1 4 9 or
4 3 3
6 6 1
1 2 18
1 3 12
1 1 36
2 2 9
Now neighbor's door numbr gives the sum.. Here all gives uniq sum except
(sum=13)
So there will be doubt in either 6 6 1 or 2 2 9
Bt as mathematician said tat
@Harshit: Check dave's solution... U'll get ur ans :)
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#includestdio.h
int main()
{
void print(int *,int *,int *,int *,int *);
static int arr[]={97,98,99,100,101,102,103,104};
int *ptr=arr+1;
print(++ptr,ptr--,ptr,ptr++,++ptr);
return 0;
}
void print(int *a,int *b,int *c,int *d,int *e)
{
printf(%d\t%d\t%d\t%d\t%d\n,*a,*b,*c,*d,*e);
}
Why the output
May be it is compiler dependent.. :)
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#includestdio.hvoid swap(char *,char *);int main(){char *ps[2]={
Hello,
Good Mornning,
};swap(ps[0],ps[1]);printf(%s \t %s\n,ps[0],ps[1]);return 0;}
void swap(char *p,char *q){char *t;t=p;p=q;q=t;}
why the output is:
HelloGood Mornning
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Ohh Sry... The qus was:
#includestdio.hvoid swap(char *,char *);int main(){char *ps[2]={
Hello,
Good Mornning,
};swap(ps[0],ps[1]);printf(%s \t %s\n,ps[0],ps[1]);return 0;}
void swap(char *p,char *q){char *t;t=p;p=q;q=t;}
why the output is:
Hello
Bt y k=0, in 2nd code???
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@Sunny: Thn y k=1 in 2nd code???
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hmm. Sry yr... Got it.. Thanx.. :) :)
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