#include<stdio.h>
#include str(x) #x
#define Xstr(x) str(x)
#define oper multiply
int main()
{
char *opername=Xstr(oper);
printf("%s",opername);
}
so firstly Xstr is expanded to str(oper)
then str(oper) is expanded to #oper now i have read that
If, however, a parameter name is preceded by a # in the replacement text,
the
combination will be expanded into a quoted string with the parameter
replaced by the actual argument...and in this case actual is also oper so
it becomes "oper"...so it should print oper .....i thnik i am mistaken
anyhre...correct???
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