Hey frnds,
I am stuck in a problem of adding two numbers using bitwise operators only.
An explanation is required.
Sanju
:)
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Refer half adder :)
*sum = a ^ b;
carry = a b;
while (carry != 0)
{
carry = 1;
a = sum;
b = carry;
sum = a ^ b;
carry = a b;
}*
On Sat, Aug 20, 2011 at 9:32 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hey frnds,
I am stuck in a problem of adding two numbers using bitwise operators only.
An
Could you post some link here ?
Sanju
:)
On Sat, Aug 20, 2011 at 9:08 AM, sagar pareek sagarpar...@gmail.com wrote:
Refer half adder :)
*sum = a ^ b;
carry = a b;
while (carry != 0)
{
carry = 1;
a = sum;
b = carry;
sum = a ^ b;
carry = a b;
}*
On Sat, Aug 20, 2011 at 9:32
+1 sagar!
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For subtraction we can use the same add function
int add(int a, int b)
{
while (a) {
a = (a b) 1;
b = a^b;
}
return b;
}
int sub(int a, int b) // add a with b's 2's
complement.
{
return (add(a, add(~b, 1)));
}
On Sat, Aug 20, 2011 at
