Please explain the output, that why is it in that form in hexadecimal form
#includestdio.h
int main()
{
printf(%d %x,-11,-11);
return 0;
}
output :
-2 fffe
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this is bec -1 in hexadecimal is
On Fri, Jul 29, 2011 at 11:37 PM, Ankur Khurana ankur.kkhur...@gmail.comwrote:
Please explain the output, that why is it in that form in hexadecimal form
#includestdio.h
int main()
{
printf(%d %x,-11,-11);
return 0;
}
output :
-2
I couldn't understand the problem .. u have used %x as indentifier that why
it is so
On Fri, Jul 29, 2011 at 11:37 PM, Ankur Khurana ankur.kkhur...@gmail.comwrote:
Please explain the output, that why is it in that form in hexadecimal form
#includestdio.h
int main()
{
printf(%d
i figured it out. I didnt know before that is was in 2's complement form .
On Fri, Jul 29, 2011 at 11:53 PM, sukhmeet singh sukhmeet2...@gmail.comwrote:
I couldn't understand the problem .. u have used %x as indentifier that why
it is so
On Fri, Jul 29, 2011 at 11:37 PM, Ankur Khurana
fffe is two's complement of 2.
Let me explain for fe and you can extrapolate it with other f's.
f =15, e =14. fe = 1110, ~fe = 0001, ~fe+1 = 0010 = 2 which
gives your answer.
Thanks Regards,
Prashant Bhutani
Senior Undergraduate
Computer Science Engineering (B.Tech)
Institute of
