A B and C have chance of failure of 20%, 30% and 40%. To activate the
machine at least two should be active. What is the probability that machine
will be active?
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Answer should be 0.212. Tell me if I am correct.
On Wed, Aug 17, 2011 at 4:30 PM, priya ramesh
love.for.programm...@gmail.com wrote:
A B and C have chance of failure of 20%, 30% and 40%. To activate the
machine at least two should be active. What is the probability that machine
will be
@romil: how did you solve this??
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Kumar's approach would not do perhaps. I simply eliminated the undesired
cases. Those include the one when none of them is active and when only one
of them is active.
@Kumar: You should have also added the term abc.
On Wed, Aug 17, 2011 at 4:39 PM, priya ramesh
love.for.programm...@gmail.com
i got 74.8% (machine works)
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@Priya: A mistake from my side. The answer should be 1-0.212 i.e. 0.788
Sorry for this mistake.
@Kumar: Yours is wrong. Check it again.
On Wed, Aug 17, 2011 at 4:42 PM, Romil ... vamosro...@gmail.com wrote:
Kumar's approach would not do perhaps. I simply eliminated the undesired
cases.
a = (1-0.2)
b = (1-0.3)
c = (1- 0.4)
a*b*(1-c) + a*(1-b)*c + (1-a)*b*c + a*b*c = 0.788
On Wed, Aug 17, 2011 at 5:08 PM, Romil ... vamosro...@gmail.com wrote:
@Priya: A mistake from my side. The answer should be 1-0.212 i.e. 0.788
Sorry for this mistake.
@Kumar: Yours is wrong. Check it
A mistake from my side as well!
Got 78.8% :)
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0.788
On Wed, Aug 17, 2011 at 5:23 PM, priya ramesh
love.for.programm...@gmail.com wrote:
A mistake from my side as well!
Got 78.8% :)
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@rohith thanks!
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take four cases :
1) A success B success C failure
2) A success B failure C success
3) A failure B success C success
4) A , B , C = success
add all the four cases :)
On Wed, Aug 17, 2011 at 5:23 PM, priya ramesh
love.for.programm...@gmail.com wrote:
A mistake from my side as well!
Got 78.8%
Sorry The probability of machine being active is 1-0.212=0.788
*Muthuraj R
IV th Year , ISE
PESIT , Bangalore*
On Wed, Aug 17, 2011 at 5:10 PM, muthu raj muthura...@gmail.com wrote:
Even i got 0.212
*Muthuraj R
IV th Year , ISE
PESIT , Bangalore*
On Wed, Aug 17, 2011 at 4:42 PM,
Even i got 0.212
*Muthuraj R
IV th Year , ISE
PESIT , Bangalore*
On Wed, Aug 17, 2011 at 4:42 PM, Romil ... vamosro...@gmail.com wrote:
Kumar's approach would not do perhaps. I simply eliminated the undesired
cases. Those include the one when none of them is active and when only one
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