Things like sensor data coming from CAN/MoST from the car is collected and
analysed in real time to avoid collisions, off-lane movement, distance
maintenance, auto parking(including parallel), slippage on road/snow, GPS
integration for perfect location and location specific data (like
What are the specs of the car. Can you please give the answer to the
following clarifying questions:
- How much distance is it suppose to travel without the driver?
- Is it suppose to run on smooth roads only or can it also run on roads
with jumps on it? On what type of road is the car most
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
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// countIslands.cpp : Defines the entry point for the console application.
//
#include stdafx.h
const int rows = 5;
const int cols = 6;
bool visited[rows][cols] = {0};
int arr[rows][cols] =
{
0,0,0,0,1,1,
0,1,0,0,0,1,
1,1,0,0,0,0,
1,0,0,0,1,1,
0,0,1,0,1,0};
void initialize()
{
for (int i=0;
@Ramakant : for which test case your code would fail??
On Tue, Jan 10, 2012 at 1:04 PM, Ramakant Sharma ramakant...@gmail.comwrote:
@atul:
no..my approach was wrongwe have to check recursively...as sravan said
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@Ramakan:
for j=0 to col
arr[0][j]=0;
for i=0 to rows
arr[i][0]=0;
assuming that given matrix is surrounded by 0 i.e indexs (i,j) for arr[][]
will start from i=1 = row and j=1 = col.
i guess your approach will work.
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0 0 0 0 0 0
0 1 0 0 1 0
0 1 1 1 1 1
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For
i liked the solution given by the reference i have provided. The thought
process is similar to mazing problem given in horowitz sahani.
nice question, however, how can this be an interview question?
If you give this solution, the interviewer would understand that you knew
the problem and hence
@atul:
0 0 0 0 0 0
--0 1 0 0 1 0 count=2
0 1 1 1 1 1
0 0 0 0 0 0
0 1 0 0 1 0
--0 1 1 1 1 1 count=2 (will not change)
but there is only one islandso it wouldnt work...
am i right?
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@ Ramakant : yupwont work.
On Tue, Jan 10, 2012 at 7:28 PM, Ramakant Sharma ramakant...@gmail.comwrote:
@atul:
0 0 0 0 0 0
--0 1 0 0 1 0 count=2
0 1 1 1 1 1
0 0 0 0 0 0
0 1 0 0 1 0
--0 1 1 1 1 1 count=2 (will not change)
but there is only one
@ Ashish : abt the solution given by reference.
well sometimes it depends , interviewer may take it +vely as he can see you
are keen to learn abt different algorithm dats why you knw it...
On Tue, Jan 10, 2012 at 7:28 PM, Ashish Goel ashg...@gmail.com wrote:
i liked the solution given by the
there is a matrix of 1 and 0
1 is a island and 0 is water
1-1 together makes one island
calculate total no of islands
Best Regards
Ashish Goel
Think positive and find fuel in failure
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To post to
Can you give an example
Say matrix is
1 1 0 0
1 1 0 0
0 0 1 1
Has it got 3 islands i.e 1-1 be in same row or they can be column wise also
i.e. 5
On Tue, Jan 10, 2012 at 7:09 AM, Ashish Goel ashg...@gmail.com wrote:
there is a matrix of 1 and 0
1 is a island and 0 is water
1-1 together
row, col, diag all
1-1-1 is a single island :)
1 1 0 0
1 1 0 0
0 0 1 1
this has only 2 islands
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Tue, Jan 10, 2012 at 7:29 AM, Ankur Garg ankurga...@gmail.com wrote:
Can you give an example
Say
this is similar to the Pixel fill algorithm usually used in photo editing
softwares (photoshop or paint )
BFS would be best approach to start with ( and check 4-adjacent or
8-includeing diagonal elements for a '1' and include that to queue. When
the queue becomes empty, increase the count by
@sravanreddy001 : Pixel fill algorithm ..what is the exact name of that
algo ???
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@Ashish Goel : didnt get it :(
1 1 0 0
1 1 0 0
0 0 1 1
1-1-1 diagonal is one island ...where is another??
1 1 0 0
1 1 0 0
0 0 1 1
these 1 will be considered one island of 2 island.??
On Tue, Jan 10, 2012 at 7:36 AM, Ashish Goel ashg...@gmail.com wrote:
row, col, diag all
1-1-1 is a
@atul: given a matrix just like above, (usually an image) the pixel values
with similar can be searched for around the current pixel, and they all can
be marked in one go,
think of an algorithm, which does the following
1) when a one is replaced by '2' manually, then algorithm changes every
@sravanreddy001 : got it ..thanks :)
On Tue, Jan 10, 2012 at 9:33 AM, sravanreddy001 sravanreddy...@gmail.comwrote:
@atul: given a matrix just like above, (usually an image) the pixel values
with similar can be searched for around the current pixel, and they all can
be marked in one go,
Scan the matrix row wise left to right
for each arr[i][j]
if(arr[i][j]==1)
{
if (!(arr[i-1][j]==1||arr[i][j-1]==1))
count++;
}
///also chk for baundary values accordingly
1 1 0 0
1 1 0 0
0 0 1 1
i think it should work..
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@Ramakant : i guess you shud include diagonal case also
for each arr[i][j]
if(arr[i][j]==1)
{
if (!(arr[i-1][j]==1 || arr[i][j-1]==1 || arr[i-1][j-1]))
count++;
}
On Tue, Jan 10, 2012 at 9:33 AM, Ramakant Sharma ramakant...@gmail.comwrote:
Scan the matrix row wise left to right
@atul:
no..my approach was wrongwe have to check recursively...as sravan said
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this is a single island, sorry for that
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Tue, Jan 10, 2012 at 9:24 AM, atul anand atul.87fri...@gmail.com wrote:
@Ashish Goel : didnt get it :(
1 1 0 0
1 1 0 0
0 0 1 1
1-1-1 diagonal is one
http://www.janaganamana.net/onedefault.aspx?bid=276
did not get it
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
+919966006652
On Tue, Jan 10, 2012 at 1:15 PM, Ashish Goel ashg...@gmail.com wrote:
this is a single island, sorry for that
Best Regards
I think RGGB is invalid as we have 4 different colors.
On Fri, Jun 10, 2011 at 10:10 AM, Harshal hc4...@gmail.com wrote:
#includeiostream
#includestring
using namespace std;
void mastermind(char* guess, char* sol, int *hits, int *pseudohits)
{
int temp[256] = {0};
int
Game of master mind: you have four balls, and four different colors, as a
solution. The user tries to guess the solution. If they guess the right
color for the right spot, it counts as a 'hit'. If it's the right color, but
the wrong spot, it counts as a psuedo-hit. For example: if the solution is
#includeiostream
#includestring
using namespace std;
void mastermind(char* guess, char* sol, int *hits, int *pseudohits)
{
int temp[256] = {0};
int len1=strlen(sol);
int len2=strlen(guess);
while(--len1+1)
(guess[len1]==sol[len1]) ? ((*hits)+=1,temp[len1] = 1) : (temp[sol[len1]]
+=
Given a function to draw a circle with input paramters as co-ordinates of
centre of the circle and r is the radius of the circle.
How will you test this function, what will be additional non-functional
test cases
Best Regards
Ashish Goel
Think positive and find fuel in failure
+919985813081
Can you please tell What are we testing here ?.
I mean to ask what is the output of the function..
On Thu, Jun 2, 2011 at 7:49 PM, Ashish Goel ashg...@gmail.com wrote:
Given a function to draw a circle with input paramters as co-ordinates of
centre of the circle and r is the radius of the
some test cases:
1) r is -ive
2) r is 0
3) test center in all four quadrants.
4) r is some very large number
On Thu, Jun 2, 2011 at 11:47 PM, Sachin Jain sachinjain...@gmail.comwrote:
Can you please tell What are we testing here ?.
I mean to ask what is the output of the function..
On
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