Can you explain a bit further with an example
On 16 May 2013 04:35, rohit jangid rohit.nsi...@gmail.com wrote:
after few attempts I think you must be getting stuck where you need a^3 +
b^3 + c^3 value in terms of abc, C1, and C2 which is possible using this
identity--
take cube of both sides and proceed
(a+b+c)^3 = C1^3 rest do it yourself.
On Thu, May 16, 2013 at 12:28 AM, Soumya Prasad Ukil
ukil.sou...@gmail.comwrote:
If a+b+c=C1 and ab+bc+ac=C2, how do you get abc?
C1,C2 are constant.
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regards,
soumya prasad ukil
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If a+b+c=C1 and ab+bc+ac=C2, how do you get abc?
C1,C2 are constant.
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regards,
soumya prasad ukil
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after few attempts I think you must be getting stuck where you need a^3 +
b^3 + c^3 value in terms of abc, C1, and C2 which is possible using this
identity--
(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)-abc]
refer this link for the proof
