yup...thank u:)
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please some1 tell how to do part 2.
On Wed, Jul 20, 2011 at 6:20 PM, kavitha nk kavithan...@gmail.com wrote:
for 3rd v can replace decrement by an increment operator!
//BE COOL// kavi
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Given the following program, MS will be printed, infinite number of
times:
int n = 20;
int i;
for (i=0; in; i--)
printf(MS);
Apply one of the following three operations one at a time such that
MS can be printed 20 times.
1. You can add only one character into it.
2.
i know 3 solns!
1) int n = 20;
int i;
for (i=0; i+n; i--)
printf(MS);
2) int n = 20;
int i;
for (i=0; in; n--)
printf(MS);
3) int n = 20;
int i;
for (i=0; -in; i--)
printf(MS);
On Tue, Jul 19, 2011 at 10:27 PM, Reynald reynaldsus...@gmail.com wrote:
Given the
n ; ~n
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how to solve part 2?
On Tue, Jul 19, 2011 at 4:16 PM, hary rathor harry.rat...@gmail.com wrote:
n ; ~n
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excuse me...can any explain y it goes to infinite loop..
with regards
naveen
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Naveen indeed it's not infinite loop but it will print MS 2^31+1 times,
right ? :)
Change it so that it prints it 20 times.
On Wed, Jul 20, 2011 at 7:39 AM, naveen ms naveenms...@gmail.com wrote:
excuse me...can any explain y it goes to infinite loop..
with regards
naveen
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