@dipankar +1
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Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad
On Fri, Aug 12, 2011 at 9:31 AM, Dipankar Patro dip10c...@gmail.com wrote:
The question is full of errors.
Provide the link, if you have copied it from somewhere.
On 11 August 2011 23:53,
What will be the output of the following program
#include
int main()
{
int m=10,p;
p=incre(incre (incre (++) incre) incre)
Printf(%d, *P);
return 0;
}
incre (int m)
{
m+=2;
return(m-2);
}
how?
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The question is full of errors.
Provide the link, if you have copied it from somewhere.
On 11 August 2011 23:53, Mani Bharathi manibharat...@gmail.com wrote:
What will be the output of the following program
#include
int main()
{
int m=10,p;
p=incre(incre (incre (++) incre) incre)
@rajkumar: thanks
#include stdio.h
#define max(a,b) ((ab)?a:b)
int main()
{
int m,n;
m=3+max(2,3);
n=2*max(3,2);
printf(%d,%d,m,n);
getchar();
return 0;
}
this gives the correct output as 6,6
On Mon, Aug 8, 2011 at 7:12 PM, Dipankar Patro dip10c...@gmail.com wrote:
relational
#include stdio.h
#define max(a,b)(ab)?a:b
int main()
{
int m,n;
m=3+max(2,3);
n=2*max(3,2);
printf(%d,%d,m,n);
getchar();
return 0;
}
y the o/p is 2,3,,please explain
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Kamakshi
kamakshi...@gmail.com
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Precedence of + is higher than ?
On Mon, Aug 8, 2011 at 3:27 PM, Kamakshii Aggarwal kamakshi...@gmail.comwrote:
#include stdio.h
#define max(a,b)(ab)?a:b
int main()
{
int m,n;
m=3+max(2,3);
n=2*max(3,2);
printf(%d,%d,m,n);
getchar();
return 0;
}
y the o/p is
#define max(a,b)((ab)?a:b)
use parenthese thn it will giv the correct o/p
On Mon, Aug 8, 2011 at 3:27 PM, Kamakshii Aggarwal
kamakshi...@gmail.com wrote:
#include stdio.h
#define max(a,b)(ab)?a:b
int main()
{
int m,n;
m=3+max(2,3);
n=2*max(3,2);
printf(%d,%d,m,n);
getchar();
thanks..got it...
On Mon, Aug 8, 2011 at 3:45 PM, jagrati verma
jagrativermamn...@gmail.comwrote:
#define max(a,b)((ab)?a:b)
use parenthese thn it will giv the correct o/p
On Mon, Aug 8, 2011 at 3:27 PM, Kamakshii Aggarwal
kamakshi...@gmail.com wrote:
#include stdio.h
#define
the statement will be transformed to :
m=3+(23)?2:3;
n=2*(32)?3:2;
which will become
m = 3 + 0 ? 2 : 3;
n = 2 * 1 ? 3 : 2;
On Mon, Aug 8, 2011 at 3:46 PM, Kamakshii Aggarwal kamakshi...@gmail.comwrote:
thanks..got it...
On Mon, Aug 8, 2011 at 3:45 PM, jagrati verma
I think you forgot to give a space between macro and it's expansion that's
why
max(a,b)(ab)?a:b
is getting expanded to null
and the above result
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Sorry that's not the reason i running that code on my machine i understood
the reason is something else
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how 2,3 any idea??
On Mon, Aug 8, 2011 at 5:09 PM, raj kumar megamonste...@gmail.com wrote:
I think you forgot to give a space between macro and it's expansion that's
why
max(a,b)(ab)?a:b
is getting expanded to null
and the above result
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3+23?2:3
so 53 hence 2 is returned bcoz of higher precedence of + over ?
Thanks
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@raj,
the preprocessed file would contain m=3+(23)?2:3 AFAIK.
So, the statement would evaluate to 3 + 1 ? 2 : 3 == 4 ? 2 : 3 ==
m = 2.
Likewise for n.
On Mon, Aug 8, 2011 at 5:21 PM, raj kumar megamonste...@gmail.com wrote:
3+23?2:3
so 53 hence 2 is returned bcoz
oops...I'm sorry.. the statement would evaluate to 3 + *0* ? 2 : 3 == *3* ?
2 : 3 == m = 2.
On Mon, Aug 8, 2011 at 5:43 PM, Shachindra A C sachindr...@gmail.comwrote:
@raj,
the preprocessed file would contain m=3+(23)?2:3 AFAIK.
So, the statement would evaluate to 3 + 1 ? 2
Since test condition will always evaluate to non-zero value (which is
considered true in c/c++) hence always first option get selected
On 8 August 2011 17:44, Shachindra A C sachindr...@gmail.com wrote:
oops...I'm sorry.. the statement would evaluate to 3 + *0* ? 2 : 3 == *3*? 2
: 3 == m
in expression (ab)?a:b---(ab) returns 1 if true and 0 if
(false) .
On Mon, Aug 8, 2011 at 6:08 PM, dilip makwana dilipmakwa...@gmail.comwrote:
Since test condition will always evaluate to non-zero value (which is
considered true in c/c++) hence always first option get selected
relational operators give 0/1 output;
(ab) - will be either 0 or 1.
similarly (a==b) will either be 0 or 1
On 8 August 2011 18:39, Anil Arya anilarya...@gmail.com wrote:
in expression (ab)?a:b---(ab) returns 1 if true and 0 if
(false) .
On Mon, Aug 8, 2011 at 6:08 PM, dilip
what is the problem with the following code
void fun(int **p)
{
static int q = 10;
*p = q;
}
int main()
{
int r = 20;
int *p = r;
fun(*p);
printf(%d, *p);
getchar();
return 0;
}
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Kamakshi
kamakshi...@gmail.com
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what s the o/p of the followin pgm?
main()
{
int i=300;
char *ptr;
ptr=i;
*++ptr=2;
printf(%d,i);
}
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i think it will be 34...
Thanks and regards,
Gajendra Dadheech
On Sun, Feb 6, 2011 at 10:15 PM, jalaj jaiswal jalaj.jaiswa...@gmail.comwrote:
@ranjane
the value of i will not change as ++ptr will execute first.
but i wonder if a char pointer can be used to store integer address... will
i do'nt know why it is printing 556.
could anyone give me the logic.
Aditya Pratap
MCA II
Delhi University
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@aditya which compiler are you using
On Sun, Feb 6, 2011 at 10:21 PM, aditya pratap
contacttoadity...@gmail.comwrote:
i do'nt know why it is printing 556.
could anyone give me the logic.
Aditya Pratap
MCA II
Delhi University
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@jalaj : gcc compiler.
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For more options,
the logic is :-
int is stored in 32 bits in our systems
300 is 0001 00101100
as ptr is character pointer, it points to lower 8 bits
and when *++ptr=2 gets executed then 0001 changes to 0010(equal to
2)
so i becomes 0010 00101100 which is 556 :D
Hi All,
char s[]={'a', 'b', 'c', 'd'};
printf(%d\n, strlen(s));
o/p is 8
can anybody plz explain why 8 ?
Mohit
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To
you didn't put an '\0' at the end of the string
strlen looks for a '\0' in the string and here it happened to be 8
bytes after the starting position of s
On 6/15/10, mohit ranjan shoonya.mo...@gmail.com wrote:
Hi All,
char s[]={'a', 'b', 'c', 'd'};
printf(%d\n, strlen(s));
o/p is 8
can
#includestdio.h
int main()
{
short int i=0;
for(i=5i=-1;++i;i0)
printf(%u\n,i);
return 0;
}
o/p coming is 1...4,294,967,295
short int is of 2 bytes
can any one plzz explain the o/p
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output on my compiler is 165535
as i=0 initialy ++i is true and so for loop condition is true and printf is
executed. when i becomes 65535 then ++i is equal to 0 and so for loop
condition becomes false.
On 5 June 2010 13:44, sharad sharad20073...@gmail.com wrote:
#includestdio.h
int main()
@divya,which compiler u r using,i m getting this o/p on gcc compiler
@mohit:loop stops at 4,294,967,295 in gcc
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If you make it unsigned short int.. then it goes to 65535 on g++/gcc
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Rohit Saraf
Second Year Undergraduate,
Dept. of Computer Science and Engineering
IIT Bombay
http://www.cse.iitb.ac.in/~rohitfeb14
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turbo c++ and my o/p is logical as well
On 5 June 2010 17:58, sharad kumar sharad20073...@gmail.com wrote:
@divya,which compiler u r using,i m getting this o/p on gcc compiler
@mohit:loop stops at 4,294,967,295 in gcc
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