@Jammy
in case of
1X
Since X is the start of a character, thus the preceding byte couldn't the
first byte of the 2-byte character.. So the MSb of the byte preceding X must
be a dont care. So in that case shouldn't we delete 2 bytes preceding X ?
On Thu, Feb 17, 2011 at 12:20 AM, bittu wrote:
>
case 1.
|-|--|
| 0 | remaining 7 bit|
|-|--|
MSB
When Character is represented by 1 Byte
case 2.
||-||-|
| 1 | last 7 bit | dont care
since it is guaranteed that l points to the start of the character.
Thus I would refer to 'X‘ as the byte l points to. Each number in the
following represents the MSB of the corresponding byte. E.g. 101X -->
the byte preceding X has MSB 1 and the byte preceding that has MSB 0
the byte preceding tha
