thanks for all for clearing my doubt :)
On Sat, May 21, 2011 at 12:07 AM, Selvakumar N
wrote:
> Two byte rep :
> 256(0001) + 1(0001)
>
> iPtr points to least significant byte , iPtr + 1 points to most significant
> byte
>
> P.S : Not verified by code
> -Selva
>
> On Fri, May 20, 2011 at 8
hi anybody reply please!!
On May 20, 6:53 pm, siva viknesh wrote:
> hi
>
> #include
> main()
> {
> int a=2,*f1,*f2;
> f1=f2=&a;
> *f2+=*f2+=a+=2.5;
> printf("\n%d %d %d",a,*f1,*f2);
>
> }
>
> for this code in code blocks IDE got 8 8 8 as op
>
> inhttp://ideone.com/ok8
Hello,
I guess
http://betterexplained.com/articles/understanding-big-and-little-endian-byte-order/
will help you to understand better. Basically the output will depend
on endianess of the system. I guess your machine were you ran this
program is little endiness machine. Let me know if you
