If you are working in C++, stl has a vector container class which will
do this. Otherwise, declare an integer pointer in the struct and use
malloc to allocate memory for it. Then you can use it like an array.
Don
On Aug 23, 11:51 pm, Arun Vishwanathan aaron.nar...@gmail.com wrote:
say that you
See if we use dynamic memory allocation then still the size of pointer will
be 4 bytes only
Mean that int* pointer still have the size equals to pointer ... malloc only
returns new alloted memory which is now only *pointed *by that pointer
check this out :- http://www.ideone.com/20ayq
On
Yes, the memory provided by malloc will not be in the structure. Only
the pointer to that memory will be in the structure. The size of a
struct is defined at compile time, so it can't be dynamically sized at
run time.
struct junk
{
int size;
int *data;
};
Somewhere in the code:
struct junk
thanks guys!
On Wed, Aug 24, 2011 at 6:37 PM, Don dondod...@gmail.com wrote:
Yes, the memory provided by malloc will not be in the structure. Only
the pointer to that memory will be in the structure. The size of a
struct is defined at compile time, so it can't be dynamically sized at
run
static_cast does not do run time type checking. That's why base
class pointer can be changed to drived class though it actually is a
base class pointer. Now its a drived class pointer, you can call
drived class functions. If you use dynamic_cast instead of
static_cast, it will throw a bad cast
Hi Amit,
Thanks for your reply.
I digged out google and found out that this kind of conversion(downcasting
from base class to derived class) can lead to unexpected behaviour. However,
I fail to understand how the print function was actually called inspite of
it not being in the base class. I
Is it right??
declare an array of pointers like, int *func[N];
and since they are pointers to functions, modify above as, int
(*func[N])();
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yup its correct...
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If the function takes in an int argument, then is it modified to
int (*func[N]) (int); ?
On Sun, Jul 31, 2011 at 2:56 PM, ankit sambyal ankitsamb...@gmail.comwrote:
yup its correct...
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@Nikhil
yes.
On Sun, Jul 31, 2011 at 3:02 PM, Nikhil Gupta nikhilgupta2...@gmail.comwrote:
If the function takes in an int argument, then is it modified to
int (*func[N]) (int); ?
On Sun, Jul 31, 2011 at 2:56 PM, ankit sambyal ankitsamb...@gmail.comwrote:
yup its correct...
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You
No. It is unsigned. -- Dave
On Jul 13, 9:28 am, Piyush Kapoor pkjee2...@gmail.com wrote:
Shouldn't the value of 1100 be -64
On Wed, Jul 13, 2011 at 4:53 PM, Anika Jain anika.jai...@gmail.com wrote:
binary equivalent of 5.2 is
101.0011001100110011001100110011(nonterminating)..
Thanks..This link is very useful.
On Jul 10, 11:40 pm, Sandeep Jain sandeep6...@gmail.com wrote:
http://www.parashift.com/c++-faq-lite/virtual-functions.html
Its one of my favorite sites... :)
Regards,
Sandeep Jain
On Mon, Jul 11, 2011 at 12:02 AM, himanshu kansal
ok,thanx
On Jul 4, 12:29 pm, Vishal Thanki vishaltha...@gmail.com wrote:
because \061 is considered as a single char in ur string..
On Mon, Jul 4, 2011 at 12:52 PM, Sangeeta sangeeta15...@gmail.com wrote:
#Iincludestdio.h
#includestring.h
main()
{
char str[]=S\061AB;
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