Here the const specifies that this is a const memeber function.
It means it does not modify its arguments.
It means it can be called for const data members.
However since a const member function is more generic than non-const member
function,it can also be called on non-const data.
On Monday, 28
complex_number const operator =(complex_number temp) const
Since, you are returning *this as reference, you have to have const
as your return type. You have made your this pointer as constant by
appending const keyword at the end of the function signature. But this
function has limitation
@amrit
Every non-static member function of a class has an implicit parameter
that is passed to the function (when called) This implicit parameter
is nothing but the this pointer. Now if you want to make the
implicit parameter (this pointer) a const, how would u do it? This
is done by placing the
the job of marked const here is to make the member function operator= as
const so it can't modify any member function values unless that member
function is mutable
@manikanta
the compiler will throw an error only when we try to modify any members
inside a const member function but here we are not
@Bhaskar u r right. I mean wen u are trying to access this function on non
constant object.
On May 28, 2012 2:08 AM, Bhaskar Kushwaha bhaskar.kushwaha2...@gmail.com
wrote:
the job of marked const here is to make the member function operator= as
const so it can't modify any member function
