he distance of a triplet (a,b,c) is defined is *max*(|a-b|, |b-c|, |c-a|)
is the correct one...
On 29 November 2011 11:09, atul anand wrote:
> @Raja : distance is defined as
>
> The distance of a triplet (a,b,c) is defined is *max*(|a-b|, |b-c|, |c-a|)
>
> OR
>
> The distance of a triplet (a,b,c
@Raja : distance is defined as
The distance of a triplet (a,b,c) is defined is *max*(|a-b|, |b-c|, |c-a|)
OR
The distance of a triplet (a,b,c) is defined is *min*(|a-b|, |b-c|, |c-a|)
On Tue, Nov 29, 2011 at 11:50 PM, Dave wrote:
> @Kumar: Let the three arrays be a, b, and c, of lengths na, n
Thanku sir...
On 29 November 2011 10:20, Dave wrote:
> @Kumar: Let the three arrays be a, b, and c, of lengths na, nb, and
> nc, respectively.
> Sort each array.
> Set ia = 0, ib = 0, ic = 0.
> Record the triplet (a[0], b[0], c[0]) as the best so far.
> Loop
>Increment the index correspondin
@Kumar: Let the three arrays be a, b, and c, of lengths na, nb, and
nc, respectively.
Sort each array.
Set ia = 0, ib = 0, ic = 0.
Record the triplet (a[0], b[0], c[0]) as the best so far.
Loop
Increment the index corresponding to the smaller of a[ia], b[ib],
and c[ic].
If the incremented i
