@Dave: Thanks alot for enlightening us!
@Manju: ya.. you are right. The same was stated by me in the my prev
reply! :-)
On Aug 29, 10:50 pm, Manjunath Manohar manjunath.n...@gmail.com
wrote:
it is compiler dependant da..the evaluation of this kind of expressions
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In php it is 19.
?php
$x=5;
printf(%d,($x++ + ++$x + $x++));
?
On Aug 28, 1:35 pm, jagadish jagadish1...@gmail.com wrote:
I ran this code..
int main() { int x=5;
printf(%d,(x++ + ++x + x++));
}
The output printed was 18 instead of 19.. Should it not be 19?
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Ya after some reading i got to know that it was implementation
dependent..
And that the answer is undefined!
On Aug 28, 5:07 pm, Chi c...@linuxdna.com wrote:
In php it is 19.
?php
$x=5;
printf(%d,($x++ + ++$x + $x++));
?
On Aug 28, 1:35 pm, jagadish jagadish1...@gmail.com wrote:
I ran
Your code violates the C standard, which says:
Between the previous and next sequence point an object shall have its
stored value modified at most once by the evaluation of an expression.
Furthermore, the prior value shall be read only to determine the value
to be stored.
Regarding postfix
