Hi Ankit,
If that is the case, I can very well say, 23 = 2 X 1 + 21
If you divide 23 by 11, remainder would be 1 and not 12.
On Thu, May 30, 2013 at 1:16 PM, Ankit Agarwal ankuagarw...@gmail.comwrote:
Hi,
23 = 11 X 1 + 12. Thus 12 would the highest remainder. Not 11
On Thu, May 30,
Hi,
23 = 11 X 1 + 12. Thus 12 would the highest remainder. Not 11
On Thu, May 30, 2013 at 10:24 AM, Sreenivas Sigharam sighar...@gmail.comwrote:
Dave's explanation was clear..and informative.. Thank you Dave..
Thank you , Soumya Prasad, for a simple but nice topic..
Thank you,
23 = 11 * 2 + 1
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Hi Nikhil,
Highest remainder can't be floor(n/2) - 1.
If n = 11, highest remainder would be 5 when it is divided by 6, but your
formula gives 4.
On Mon, May 27, 2013 at 8:16 PM, Nikhil Kumar niksingha...@gmail.comwrote:
Since we need to divide so the quotient should be at least 1, and we need
Hi,
Number 23: = 11 * 1 + 12 Number/2 = 11.5
Number 17: = 9 * 1 + 8 Number/2 = 8.5
So, its neither floor(n/2) +- 1, nor ceil(n/2) +- 1
On Wed, May 29, 2013 at 2:19 PM, Ankit Sambyal
ankitsambyal1...@gmail.comwrote:
Hi Nikhil,
Highest remainder can't be floor(n/2) - 1.
If n = 11,
The highest remainder when dividing n by a number less than n is
floor((n-1)/2).
For n = 11, floor((11-1)/2) = floor(10/2) = floor(5) = 5.
For n = 17, floor((17-1)/2) = 8
For n = 23, floor((23-1)/2) = 11
For n = 12, floor((12-1)/2) = floor(11/2) = floor(5.5) = 5.
Etc.
Dave
On Wednesday,
@Dave:
For N = 23, the highest remainder is 12, not 11
On Thu, May 30, 2013 at 5:02 AM, Dave dave_and_da...@juno.com wrote:
The highest remainder when dividing n by a number less than n is
floor((n-1)/2).
For n = 11, floor((11-1)/2) = floor(10/2) = floor(5) = 5.
For n = 17, floor((17-1)/2)
Hi Ankit,
for 23, how can the remainder be 12 ? Can you elaborate more ?
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On Thu, May 30, 2013 at
Dave's explanation was clear..and informative.. Thank you Dave..
Thank you , Soumya Prasad, for a simple but nice topic..
Thank you,
Sigharam.
On Thu, May 30, 2013 at 10:16 AM, Sanjay Rajpal sanjay.raj...@live.inwrote:
Hi Ankit,
for 23, how can the remainder be 12 ? Can you elaborate more
Since we need to divide so the quotient should be at least 1, and we need
greatest remainder, so we need the least no. which will give the quotient 1
upon dividing and that would be the no. you described.
Also you would have noted the greatest remainder would be floor(n/2)-1 .
On Thursday, 16
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