@mac
Path always should be go through the root of the tree?
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Why??? It doesn't help to solve problem. You are already have tree structure
with parent links. Taunt.
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Tree structure already have parent node link. Even we reconstruct the tree
as linked list we are not allowed to achieve the goal. Path can be combined
using non-contigious (created from inorder traversal) elements. The only
solution is using DP with O(MAX_SUM_VALUE) extra space for each node.
On Mon, Jan 3, 2011 at 6:08 PM, juver++ avpostni...@gmail.com wrote:
Tree structure already have parent node link. Even we reconstruct the tree
as linked list we are not allowed to achieve
Normal tree node does not contain link to its parent. I am not saying
convert tree into linklist
On Tue, Jan 4, 2011 at 8:13 AM, rahul patil
rahul.deshmukhpa...@gmail.comwrote:
On Mon, Jan 3, 2011 at 6:08 PM, juver++ avpostni...@gmail.com wrote:
Tree structure already have parent node link. Even we reconstruct the tree
as linked list we are not allowed to achieve
Normal tree node
On Sun, Jan 2, 2011 at 8:30 PM, Akash Agrawal akash.agrawa...@gmail.comwrote:
I have written a kinda messed-up code for the same. Which is basically a
bottom-up approach.
Please find the same as attached. Some boundary conditions might be missed
and code can be written in a more decorated,
No , we had to find all the paths . Some paths could include the root .
On Tue, Dec 28, 2010 at 11:12 PM, yq Zhang zhangyunq...@gmail.com wrote:
I think the original question says Path can go from left subtree tree ,
include root and go to right tree as well. This should mean the path must
There are 3 paths exist in bst, post, pre and inorder.
store all these paths and find contiguous sum(and set of elements
which leads to this sum) and check if it equals to given sum, then
that is path.
On Dec 27, 6:48 pm, mohit ranjan shoonya.mo...@gmail.com wrote:
any hint for below question
Incorrect. Path can be combined from the several traversal algorithm's
output.
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Not clear what path you are referring to.
Question. Should the path include root value always? (What is problem
with only left or only right path (not containing root))
In your example for 16 one more path can be 0 1 5 10 as
well. Should algo return all the paths or just first one.
I think the original question says Path can go from left subtree tree ,
include root and go to right tree as well. This should mean the path must
include the root.
On Tue, Dec 28, 2010 at 4:52 AM, shanushaan er.srivastavaro...@gmail.comwrote:
Not clear what path you are referring to.
And of course boundary cases(leaf nodes) are to be handled. For a leaf
node 'i', ok[i][j]=1(if j==v[i]), 0 otherwise!!!
On Dec 28, 11:04 pm, suhash suhash.venkat...@gmail.com wrote:
I think this can be solved using dp. Consider the subtree rooted at
node 'i'. Let ok[i][j] be a boolean (0 or 1)
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