Thanks
But it is used bigint but find a value without using bigint.
On 4 September 2010 11:54, Shravan wrote:
> http://ideone.com/4wj5t
>
> On Sep 3, 10:52 pm, Discover wrote:
> > But how the number(in decimal form) will be displayedif ques
> > demands so.
> >
> > On Sep 2, 1:49 pm, saurabh
http://ideone.com/4wj5t
On Sep 3, 10:52 pm, Discover wrote:
> But how the number(in decimal form) will be displayedif ques
> demands so.
>
> On Sep 2, 1:49 pm, saurabh singh wrote:
>
>
>
> > Suppose the number of shifts be x.
> > Also let the integer be represented by 16 bits on that machine
But how the number(in decimal form) will be displayedif ques
demands so.
On Sep 2, 1:49 pm, saurabh singh wrote:
> Suppose the number of shifts be x.
> Also let the integer be represented by 16 bits on that machine.
> Now take int n= (int)(x/16 + 0.5), to take the upper cap on result :) .
> S
can post the c program of what u ave said above
On 2 September 2010 16:06, vikash jain wrote:
> nice...
>
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Suppose the number of shifts be x.
Also let the integer be represented by 16 bits on that machine.
Now take int n= (int)(x/16 + 0.5), to take the upper cap on result :) .
SO having 2^x will be same as doing 2<<(x-1) so essentially if we represent
the resultant number in a linked list of nodes, wher
I think it will be 1< wrote:
> Maybe you misunderstand the question.
> The question is how to compute 2^X where 0 <= X <= 9?
> How?
>
> On Wed, Sep 1, 2010 at 10:48 PM, Ruturaj wrote:
> > a 5 digit number is of order 10^5 which is << 10^16 of which int in C
> > is of size.
> > Just multip
Maybe you misunderstand the question.
The question is how to compute 2^X where 0 <= X <= 9?
How?
On Wed, Sep 1, 2010 at 10:48 PM, Ruturaj wrote:
> a 5 digit number is of order 10^5 which is << 10^16 of which int in C
> is of size.
> Just multiply both numbers.
>
> On Sep 2, 10:39 am, pras
a 5 digit number is of order 10^5 which is << 10^16 of which int in C
is of size.
Just multiply both numbers.
On Sep 2, 10:39 am, prasad rao wrote:
> Program that takes a 5 digit number and calculates 2 power that number and
> prints it and should not use the Big-integer and Exponential Function'
