@Vengadanathan:
I think you should see this link
http://c-faq.com/expr/seqpoints.html
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Thanks and Regards
*Devansh Gupta*
*B.Tech Third Year*
*MNNIT, Allahabad*
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@Devansh:
Nice post..
Regards,
Abhishek Khattri
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z is equal to 6 as both are post increment. However, if one of these
was pre-increment, output would have been undefined.
On Jul 19, 9:39 am, sagar pareek sagarpar...@gmail.com wrote:
you are using post increment which increments th evariable in next line :)
(except for the case of printf();
z=++x+x++ //with x=2
gives z=6 and x=4
On Tue, Jul 19, 2011 at 10:32 AM, rogu3 manikanta...@gmail.com wrote:
i think ++x+x++ works fine.
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Your answer lies in the above few posts:)
On Tue, Jul 19, 2011 at 10:37 AM, sagar pareek sagarpar...@gmail.comwrote:
z=++x+x++ //with x=2
gives z=6 and x=4
On Tue, Jul 19, 2011 at 10:32 AM, rogu3 manikanta...@gmail.com wrote:
i think ++x+x++ works fine.
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what??
On Tue, Jul 19, 2011 at 10:39 AM, saurabh singh saurab...@gmail.com wrote:
Your answer lies in the above few posts:)
On Tue, Jul 19, 2011 at 10:37 AM, sagar pareek sagarpar...@gmail.comwrote:
z=++x+x++ //with x=2
gives z=6 and x=4
On Tue, Jul 19, 2011 at 10:32 AM, rogu3
pre increment x becomes 3 then post increment x remains 3 gives z the value
6.When this thing done increases x to4.
Though all examples given above are undefined(and total crap) as per C is
concernd.So don't mind if you see a compiler produces an assembly code that
crashes ur computer on writing
