Won't we require to check recurring till at-least two complete iterations of
recurrence pattern.
Also what's the division logic are we going to use ?
In all modern day processor systems, we are likely to have a math
co/sub-processor which will efficiently crunch numbers and round them off to
our d
thanks anurag :)
On 12 June 2010 20:07, Anurag Sharma wrote:
> Since we are given numerator 'n' and denominator 'd' separately already.
> and considering n and d as integers and d!=0 we can safely assume n/d as
> either a terminating fraction or a non terminating but recurring fraction,
> in whi
Since we are given numerator 'n' and denominator 'd' separately already. and
considering n and d as integers and d!=0 we can safely assume n/d as either
a terminating fraction or a non terminating but recurring fraction, in which
case we have to find the recurring digits of the fraction.
Now what
@anurag
i dint get ur approach..which numerator n denominator u r talking about..plz
explain.. thanks in advance
On 11 June 2010 08:57, Anurag Sharma wrote:
> Please note that the fractional repeating part is recurring. and so that
> 4th temporary variable assignment will be this way->
> temp=x
Please note that the fractional repeating part is recurring. and so that 4th
temporary variable assignment will be this way->
temp=x*1 - x= 233456.34563456... - 23.34563456 = 233433.0 ( mark
the fractional part is 0 now since the infinitely repeating 3456... will get
cancelled)
In this c
One solution that is very simple is: while doing division keep storing the
dividend. if any one dividend is repeated stop there and extract the part
between first occurrence digit before new occurrence.
Example:
7/9
7) 9 (1.*285714*28
7
--
20
14
---
it will work as the number after the decimal digit is recurring as in this
case 3456 is recurring that is the the number is not just 23.34563456, its
23.3456345634563456.. so after subtraction it will give zero as the
decimal part.
On Thu, Jun 10, 2010 at 8:55 AM, Veer Sharma wrote:
> See
Seems it wont work...
x=23.34563456
temp = x*100 -x = 233.4563456 - 23.34563456 = 210.11071104
temp = x*100 -x = 2334.563456 - 23.34563456 = 2311.21782144
temp = x*1000 -x = 23345.63456 - 23.34563456 = 23322.28892544
temp = x*1 -x = 233456.3456 - 23.34563456 = 233432.6544
temp = x*10
multiply the original number x=23.34563456
Anurag Sharma
On Wed, Jun 9, 2010 at 10:36 PM, Veer Sharma wrote:
> One question:
>
> No x = 23.34563456
> temp = x X 10 = 233.4563456
> temp = temp - x = 210.11071104
> decimal part zero? No.
> Now multiply the no. with 100. Which no? original x (= 23.
One question:
No x = 23.34563456
temp = x X 10 = 233.4563456
temp = temp - x = 210.11071104
decimal part zero? No.
Now multiply the no. with 100. Which no? original x (= 23.34563456) or
new no. temp (=210.11071104)?
On Jun 9, 8:12 pm, divya jain wrote:
> multiply the no. with 10 nd store in tem
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