I think this works if elements are sorted . Is it correct?
On Mon, Feb 1, 2010 at 5:07 PM, sachin sachin_mi...@yahoo.co.in wrote:
A way to solve this problem would be using xor(exclusive OR)
xor all the elements from 1 to n.Call it A
xor all the elements of the array into a variable B
Now
No. This works for all cases. Xor is commutative.
On 2010-2-5 13:37, srinivas chintagunta wrote:
I think this works if elements are sorted . Is it correct?
On Mon, Feb 1, 2010 at 5:07 PM, sachin sachin_mi...@yahoo.co.in
mailto:sachin_mi...@yahoo.co.in wrote:
A way to solve this problem
Yup Terence is right.
On Fri, Feb 5, 2010 at 11:42 AM, Terence technic@gmail.com wrote:
No. This works for all cases. Xor is commutative.
On 2010-2-5 13:37, srinivas chintagunta wrote:
I think this works if elements are sorted . Is it correct?
On Mon, Feb 1, 2010 at 5:07 PM, sachin
A way to solve this problem would be using xor(exclusive OR)
xor all the elements from 1 to n.Call it A
xor all the elements of the array into a variable B
Now missing element = A xor B
It works this way
xor-ing an element with itself gives 0(p xor p=0)
xor-ing an element with 0 gives the element
