[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-19 Thread mimouni
dear sir this is the first part of the demonstration: http://sites.google.com/site/isomorphismproject/Home/Uned%C3%A9monstrationplusd%C3%A9taill%C3%A9_eng.pdf On 19 juil, 16:42, Miroslav Balaz wrote: > No you do not have to explain 1. > It can be done easily by showing that distance d(a,b) >=d(f

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-19 Thread Miroslav Balaz
No you do not have to explain 1. It can be done easily by showing that distance d(a,b) >=d(f(a),f(b)) let shortest path be a,x_1,x_2,x_3, ... x_k,b then f(a),f(x_1),f(x_2),f(x_3),...f(x_k),f(b) is also path, and d(f(a),f(b))>=d(a,b) by using fact that f has inverse function sice it is bijection.

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-19 Thread mimouni
dear sir, give me a little time (2 days or 3 days) to give a more detailed demonstration. but I must know two things if you enjoy: 1) are that I must show that the distance between A and B equals the distance between f (A) and f (B)? 2) are that the algorithm is to explain or not? and thank you

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-18 Thread Miroslav Balaz
Now it is more clear to me. So labeling of vertex is set of n fourtuples. Still i do not understand the proof( first implication trivialy holds, because such labeling is in variant to permutation) 2) A and B have the same labeling. If the labeling of A in the pseudo-tree x is nhmb, labeling B in

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-17 Thread mimouni
On 16 juil, 18:19, Miroslav Balaz wrote: > I think that there is logical error, in the proof what do you think about > it? > f(A)=B iff A and B have the same labelig, but what if there are 3 vertices > with the same labeling? say A,B,C > then F(A)=B and F(A)=C > > you forget to quantify the f.

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-17 Thread mimouni
I believe that everything is clear: if I should seek the existence of the isomorphism between two graphs G and H, I should generate the label of each vertex of G and each vertex of H. .. On 16 juil, 18:26, Miroslav Balaz wrote: > And also you should answer the main question , how will you find t

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-17 Thread mimouni
example of a triangle: A - B A - C B - C here the three vertices A, B and C have the same labeling. On 16 juil, 18:19, Miroslav Balaz wrote: > I think that there is logical error, in the proof what do you think about > it? > f(A)=B iff A and B have the same labelig, but what if there are 3 verti

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-17 Thread mimouni
example of a triangle: A - B A - C B - C here the three vertices A, B and C have the same labeling. On 16 juil, 18:19, Miroslav Balaz wrote: > I think that there is logical error, in the proof what do you think about > it? > f(A)=B iff A and B have the same labelig, but what if there are 3 verti

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-17 Thread mimouni
example of a triangle: A-B A-C A-B here it is clear that the vertex A, B and C have identical labeling. On 16 juil, 18:19, Miroslav Balaz wrote: > I think that there is logical error, in the proof what do you think about > it? > f(A)=B iff A and B have the same labelig, but what if there are 3

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-16 Thread Miroslav Balaz
And also you should answer the main question , how will you find the automorphism function? Or how would you use the theorem only to decide if there exists an isomorphism? 2009/7/16 Miroslav Balaz > I think that there is logical error, in the proof what do you think about > it? > f(A)=B iff A an

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-16 Thread Miroslav Balaz
I think that there is logical error, in the proof what do you think about it? f(A)=B iff A and B have the same labelig, but what if there are 3 vertices with the same labeling? say A,B,C then F(A)=B and F(A)=C you forget to quantify the f. I think everyone stops reading it if you will have such er

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-15 Thread mimouni
is aviable in ;http://www.wbabin.net/science/mimouni2e.pdf On 14 juil, 19:25, Miroslav Balaz wrote: > Graph isomorphism is not very good problem, because for human generated > graphs the algorithhm for tree-isomprphism wlll work. > But that is only my personal opinion. > > But it is hard to unde

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-15 Thread mimouni
you can consult in: http://www.wbabin.net/science/mimouni2e.pdf and I finished on implimentation schedule a php (to find the labels for a graph exceeds 5000 vertices). On 14 juil, 19:25, Miroslav Balaz wrote: > Graph isomorphism is not very good problem, because for human generated > graphs the

[algogeeks] Re: polynomial algorithme for isomorphic graphs

2009-07-14 Thread Miroslav Balaz
Graph isomorphism is not very good problem, because for human generated graphs the algorithhm for tree-isomprphism wlll work. But that is only my personal opinion. But it is hard to understand your algorithm. Mainly because i do not understand the words you are using peak-? summit-? pseudo tree-?