hi all,
i really liked the answers of
sunny, and
sachin midha
gr8 answers.
but i guess as per the requirement, sachin's answer is perfect.
B.Srinivas
B.E. Computer engineering
Mumbai University
On Sat, Mar 5, 2011 at 5:55 PM, Bhavesh agrawal agr.bhav...@gmail.comwrote:
funny but correct ,i
Using GOTO and loops it the same, cause loops are expanded to GOTO/JMP
statements.
Doing it just with recursion is interesting.
Try sorting number without using loops or goto.
Here is the complete problem.
Take in n numbers as input and sort them, without using dowhile,
while, for or goto. No
@ Ruturaj: Your Problem's Solution.. :)
public class Sorting
{
public static void main(String arg[])
{
int[] a = {2,4,5,1,7,3};
a = checkNumber(0,1,a);
// to Print an Array
for(int k=0;ka.length;k++)
funny but correct ,i have a code of 100 lines of file named b.cpp
so i use awk script to print only no. of lines and i got the exact desired
result .
#includecstdlib
using namespace std;
int main()
{
system(awk '{print NR}' b.cpp);
}
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The method that I have given you, can print as many numbers as you
want, depending upon how many objects you create.
Yes with this method you'll have to create 100 objects of the dummy
class,
that can be easily created using dummy d[100]
So that makes the method very effective shows how much
use recursion.
On Tue, Mar 1, 2011 at 5:13 PM, bittu shashank7andr...@gmail.com wrote:
here we go
void main()
{
int i;
i=1;
loop:
printf(%d, i)
(i100)? i++: return 0;
go to loop;
}
Thanks Regards
Shashank Mani The Best Way to Escape From The Problem is to Solve
it
--
Hey all...
I have another method, which will use the power of c++...
class dummy{
static int objectCount;
dummy(){ cout ++objectCount endl; }
}
int dummy::objectCount = 0;
Now create as many objects as required, and as you create a new
object, the total count of objects instantiated till now
#includeiostream
int i=1;
int main()
{
printf(%d\n,i++);
return i==100?0:main();
}
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Himanshu Sachdeva
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should be i==101 instead.
On 3/1/11, Himanshu Sachdeva himansh.sachd...@gmail.com wrote:
#includeiostream
int i=1;
int main()
{
printf(%d\n,i++);
return i==100?0:main();
}
--
Himanshu Sachdeva
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Himanshu Sachdeva
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Rather than iostream, include stdio.h, because we can't call main()
from main() in c++, but we can do that in C.
Best Regards,
Sachin Midha
On Mar 1, 10:49 pm, Himanshu Sachdeva himansh.sachd...@gmail.com
wrote:
#includeiostream
int i=1;
int main()
{
printf(%d\n,i++);
return
@himanshu: you are using recursive call. And in problem it is mentioned that
you can't use recursion.
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Sorry. Didn't read the problem statement correctly.
On 3/1/11, MANNU manishkr2...@gmail.com wrote:
@himanshu: you are using recursive call. And in problem it is mentioned that
you can't use recursion.
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Algorithm
@bittu
please read the thread carefully. It was mentioned not to use GOTO
statement.
On Tue, Mar 1, 2011 at 5:13 PM, bittu shashank7andr...@gmail.com wrote:
here we go
void main()
{
int i;
i=1;
loop:
printf(%d, i)
(i100)? i++: return 0;
go to loop;
}
Thanks Regards
Shashank
how will you create 100 objects of dummy class. Can you write pseudo code
for that?
On Tue, Mar 1, 2011 at 11:11 PM, Sachin Midha sachinmidha1...@gmail.comwrote:
Hey all...
I have another method, which will use the power of c++...
class dummy{
static int objectCount;
dummy(){ cout
So do you want to say the code below is not using recursion?
#includeiostream
int i=1;
int main()
{
printf(%d\n,i++);
return i==100?0:main();
}
On Tue, Mar 1, 2011 at 11:27 PM, Sachin Midha sachinmidha1...@gmail.comwrote:
Rather than iostream, include stdio.h, because we can't call main()
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