@harit
random number means its output cant be predicted,it doesnt mean that the
probability will be equal for any number of test runs.
e.g consider random number between 3-5 for 3 test runs
if the first output is 4
second is 3
then to ensure same probability third output must be 5
which makes random number predictible
Now, in my case rand() generates 0 and 1randomly
So the result may depend upon what the output of rand() is at each stage.
In your code to get random number between 0 and 1 replace rand() by rand()%2
On Tue, Oct 6, 2009 at 6:54 PM, harit agarwal <agarwalha...@gmail.com>wrote:
> neeraj and anilkumarmyla
> yr codes r not giving numbers with equal probability
> here is the code
>
>
> #include<iostream>
> #include<time.h>
> #include<stdlib.h>
> using namespace std;
> int random(int a,int b)
> {
> return (a+(rand()%(b-a+1)));
> }
> int random1(int a,int b)
> {
> int mid;
> if(a==b)
> return a ;
> mid = a + (b-a)/2 ;
>
if( rand() )
>
// replace by if( rand()%2 )
return random(mid,b) ;
> else
> return random(a,mid) ;
> }
> main()
> {
> int a,b;
> cout<<"enter range\n";
> cin>>a>>b;
> srand(time(0));
> for(int i=0;i<10;i++)
> cout<<random(a,b)<<"\t";
> cout<<endl;
> for(int i=0;i<10;i++)
> cout<<random1(a,b)<<"\t";
> }
>
> input :
> 2 5
> output:
> 5 4 3 3 5 3 5 3 3 5
> 5 5 4 5 5 5 3 3 5 3
>
>
>
> >
>
--
Neeraj Kumar
B.Tech (Part III)
Department of Computer Sc. & Engineering
IT-BHU,Varanasi
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