modify(char a[],char *b) { a[0]='a'//gives runtime error why? b[0]='b'//gives runtime error
} main() { char p[]="hello"; char *x="hello"; x[0]='x';//will give run time error i know why p[0]='p' //works fine i know why modify("string","pointer"); } why un function modify both the assignments give runtiie error are both a and b acting as pointers to some constant strings -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.