hi
Can anyone help me find out the time complexity of recursive gcd algorithm
(using euclid's algo)
i.e. for the following program :
int gcd(int n,int m) //given nm
{
if(n%m==0)
return m;
else
return gcd(m,n%m);
}
i think the soln is lg(a*b) but have no idea how..
--
You
The complexity is O(h^2) where h is the number of digits in the smaller
number *m* in base 10.
On Tue, Nov 13, 2012 at 3:34 PM, Shruti Gupta fundooshr...@gmail.comwrote:
hi
Can anyone help me find out the time complexity of recursive gcd algorithm
(using euclid's algo)
i.e. for the
Here the time complexity of the solution should be O(n * log(n))
http://www.geeksforgeeks.org/archives/21781
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Sorting takes linear time, but it doesnt get repeated n times,
it is like - T(n) = 2*T(n/2) + O(n)
worst case solution is O(n^2)
it is similar to quick sort
On Mon, Nov 5, 2012 at 9:15 PM, rahul sharma rahul23111...@gmail.comwrote:
dude n for build tree and n in this for finding
building tree will take O(n) time but for each node we need to find max i.e
i = max (inorder, start, end);
so complexity in worst case will we O(n^2).
On Tue, Nov 6, 2012 at 12:26 AM, shady sinv...@gmail.com wrote:
Sorting takes linear time, but it doesnt get repeated n times,
it is like -
Hello
I was going through this link
http://www.geeksforgeeks.org/archives/3187
Wonder what is the time complexity for this..?Can anyone explain
Regards
Ankur
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this doesn't seem like level order printing, because you are simply
printing the tree starting with the children as the root node.
On Sat, Nov 19, 2011 at 12:57 PM, Ankuj Gupta ankuj2...@gmail.com wrote:
What is the time complexity of this code for Level Order Traversal.
void
the complexity is N^2
for each level you are traversing all the nodes below that level. for nth
level , you have to traverse all n-1 nodes.
so O(N^2)
better to use queue , we can traverse level order in O(n).
On Sat, Nov 19, 2011 at 4:58 PM, shady sinv...@gmail.com wrote:
this doesn't seem like
@shady : i guess code is fineit will print the node only when level=1 ,
and level is in loop so for level = 1 it will print root
when level=2 then it will print all nodes at level 2 and so on...
i guess we can optimize this code..
On Sat, Nov 19, 2011 at 3:28 PM, shady sinv...@gmail.com
void printLevelOrder(BinaryTree *root) {
node *temp;
enqueue(root);
while((temp=dequeue()) != NULL)
{
printf(%d ,temp-data);
if (temp-left)
{
enqueue(temp-left);
}
if ( temp-right)
{
enqueue(temp-right);
}
}
}
i guess this approach is much
Its NlogN if balanced.. Else N^2
For each element it's visiting at most log N elements.(assuming balanced)
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@ sravanreddy001
complexity is O(N^2) whether tree is balanced or not doesn't matter
For each level it's visiting elements. all elements upto n-1 level .
i dont know from where u got the concept of logn , the code is not
making any decision to go in left or right , it is going in left and
I think any traversal has o(n) complexity as we traverse all the
nodes.There is no skipping of nodes.Very simple logic:)
On Sun, Nov 20, 2011 at 9:57 AM, tech coder techcoderonw...@gmail.comwrote:
@ sravanreddy001
complexity is O(N^2) whether tree is balanced or not doesn't matter
For each
What is the time complexity of this code for Level Order Traversal.
void printLevel(BinaryTree *p, int level) {
if (!p) return;
if (level == 1) {
cout p-data ;
} else {
printLevel(p-left, level-1);
printLevel(p-right, level-1);
}
}
void printLevelOrder(BinaryTree *root) {
What is the time complexity of morris traversal ?
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for(i=0;in;i++)
for(j=0;ji*i;j++)
for(k=0;kj;k++)
sum++;
Is itn^5 log n . n * (n^2 log n) * (n^2 log n) ???
correct me if i m wrong? also anybody can tell some easy approach to tackle
these ques ?? I worked out for some values of n and arrived at the ans.
Its quite long... but its simple...
pls tell me its worst case time complexity..!!!
#includestdio.h
#includestring.h
#includeconio.h
#includestdlib.h
int check(char *p,int n)// this function checks for pallindromicity of
the string passed.
{
char a[100],b[100];
int k;
for(k=0;k=n;k++)
Hi All,
Can someone explain about the time complexity of Merge sort(Linked list with
billions of node)?
There is no way to find the middle of sub-list without traversing
completely.
Please clear my doubts.
Thanks Regards,
Anantha Krishnan
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Merge sort is often the best choice for sorting a linked list. Reason
because it requires only Θ(1) extra space only and generally beats
other algorithms like quicksort,heapsort for sorting linked lists. The
overall complexity remain O(N log N) even in the worst case
On 6/23/11, Anantha Krishnan
I googled a better explaination for this and found this...
hope this will be useful...
Sorting a LinkedList is different from sorting an Array as you can not
make index based references to any arbitrary item in the List. Instead
you need to remember the items during each recursive step and then
Also u can refer
http://www.chiark.greenend.org.uk/~sgtatham/algorithms/listsort.html
On 6/24/11, Piyush Sinha ecstasy.piy...@gmail.com wrote:
I googled a better explaination for this and found this...
hope this will be useful...
Sorting a LinkedList is different from sorting an Array as you
Thanks. I think if we make k traversals at each step it would be O(n * n/2 *
log n)
If I know value of K we can do it in O(n log n) I agree.
What will be the time complexity if there are billion nodes i.e even if i
know node count i cannot store it in integer variable?
Thanks Regards,
Anantha
What is the time complexity of sqrt function of c++?
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Greetings
How many of you guys calculate the time complexity of an algorithm
before implementing it on a day to day basis?
When you review your code, before committing it to the live source
code base, does anybody discuss the time complexity?
Would love to hear your interesting experiences..
yes ofcourse.the efficiency of my code is always a concern to me...
On 17 August 2010 18:54, Ashutosh Tamhankar asshuto...@gmail.com wrote:
Greetings
How many of you guys calculate the time complexity of an algorithm
before implementing it on a day to day basis?
When you review your
Hello .
How to decide insertion sort takes less cost of time
for small input size.
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What is the time complexity of insertion and deletion in
1. Linked list
2. Queue
3. Queue implemented using a linked list
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To
Linked List: Insertion O(n) deletionO(n)
Queue using linked list : Insertion O(1) deletion O(n).
On Tue, Jun 8, 2010 at 1:38 AM, Raj N rajn...@gmail.com wrote:
What is the time complexity of insertion and deletion in
1. Linked list
2. Queue
3. Queue implemented using a linked list
--
Hi all,
i have 3 short questions that i would like answered.
1) What is the best case complexity for a tree of degree(4).
I said B(n) = n.
Is it B(n)=1? I think it is the first case
2) Also, is the average case for a doubly circular queue A(n)=n+1/2
3) Lastly, is the worst-case of a search
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