Variable start and hex_buf point to string constant, which can not be
modified.
Change:
char *start = "12.12.12.12.12976665176069214";
char *hex_buf = "65003a0a";
to:
char start[] = "12.12.12.12.12976665176069214";
char hex_buf[] = "65003a0a";
On 2011-2-15 15:01, dinesh bansa
got it clear.. thanks guys.
On Tue, Feb 15, 2011 at 1:46 PM, jagannath prasad das
wrote:
> here start is pointing to string constant which is created in read-only
> memory which can't be changed.so modifying it in the for loop causes
> segmentation fault
> declare it as a array type
>
>
> On Tue,
here start is pointing to string constant which is created in read-only
memory which can't be changed.so modifying it in the for loop causes
segmentation fault
declare it as a array type
On Tue, Feb 15, 2011 at 12:36 PM, rahul wrote:
> char *start is const char *start, pointer to const char, u c
char *start is const char *start, pointer to const char, u can't derefernce
it and change it.
take a char start[256].try this.
On Tue, Feb 15, 2011 at 12:31 PM, dinesh bansal wrote:
> Hi All,
>
> Can you please point me to the error in the following function. It gives
> segmentation fault.
>
> i
Hi All,
Can you please point me to the error in the following function. It gives
segmentation fault.
int main()
{
char *start = "12.12.12.12.12976665176069214";
char *hex_buf = "65003a0a";
unsigned short i, j = 0;
int new_len2 = strlen(hex_buf);
for (i = 0; ((j+1) < new_len2);
