in case of -ve numbers irrspectiveof size of compilerits repesented as
in remanig space apart from the space of binaryequivalent of number.hence u
get
On Sun, Aug 8, 2010 at 9:37 PM, navin wrote:
> Assunming, integer is 2 byte, What will be the output of the program?
>
> #include
>
> i
sign bit gets extended in case of negative numbers
On Sun, Aug 8, 2010 at 9:37 PM, navin wrote:
> Assunming, integer is 2 byte, What will be the output of the program?
>
> #include
>
> int main()
> {
>printf("%x\n", -1>>1);
>return 0;
> }
>
> [A].
> [B].0fff
> [C].
>
Assunming, integer is 2 byte, What will be the output of the program?
#include
int main()
{
printf("%x\n", -1>>1);
return 0;
}
[A].
[B].0fff
[C].
[D].fff0
Answer: Option A
i dont understand why it produces
actually -1 =
there shoud be one bit zero ( i
