FUNC2(i) = i==0?i*(i-1*(i-1-1))
8==0?1:8*(8-1*(8-1-1))
8==0?1:8*(8-6)
8==0?1:8*2
8==0?1:16
hence it will return 16
On Sun, Aug 21, 2011 at 11:40 AM, SuDhir mIsHra
sudhir08.mis...@gmail.comwrote:
#includestdio.h
#define FUNC1(i) (i*(i-1))
#define FUNC2(i) (i==0?1:i*FUNC1(i-1))
main()
{
+1 to sagar
Sanju
:)
On Sun, Aug 21, 2011 at 3:26 AM, sagar pareek sagarpar...@gmail.com wrote:
FUNC2(i) = i==0?i*(i-1*(i-1-1))
8==0?1:8*(8-1*(8-1-1))
8==0?1:8*(8-6)
8==0?1:8*2
8==0?1:16
hence it will return 16
On Sun, Aug 21, 2011 at 11:40 AM, SuDhir mIsHra
doesn it work like below ?
func2(8)= 8 * func1(7)
func1(7)= 7*6
so i=8*7*6???
On Sun, Aug 21, 2011 at 3:58 PM, Sanjay Rajpal srn...@gmail.com wrote:
+1 to sagar
Sanju
:)
On Sun, Aug 21, 2011 at 3:26 AM, sagar pareek sagarpar...@gmail.comwrote:
FUNC2(i) = i==0?i*(i-1*(i-1-1))
Nopes, its a funda of PRE-PROCESSOR directives.
Look before the object code is generated for the program, all the occurences
of the MACROs are replaced with their expansions as such as in the
definition.
So what u r doing is completely wrong.
For more info on MACROs, refer any text book of C.
