This is one of the old puzzles, but I couldn't reason out how ppl get
to the answer they say.

"An ant has to crawl from one corner of a room to the diametrically
opposite corner as quickly as possible. If the dimensions of the room
are 3 x 4 x 5, what distance does the ant cover?"

I think the answer is min( ( sqrt(sqr a + sqr b) + c ), (sqrt(sqr b +
sqr c) + a), (sqrt(sqr c + sqr a) + b))

but some people say the answer is min( ( sqrt(a + b) + c ), (sqrt(b +
c) + a), (sqrt(c + a) + b)).

How is that?

[I used http://gurmeetsingh.wordpress.com/2008/09/12/puzzle-ant-in-a-room/
to format this question]

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