Re: [algogeeks] google os ques on pipelining

2011-09-26 Thread bharatkumar bagana
for the first instruction : 150+5+120+5+160+5+140=585 ns for the rest of the instructions , though pipeline max(150,120,160,140)=160 (160+5)*999=164835 ns we assume that there will be no extra stalls existed in our system -585 + 164835 =165420 ns =165.4 us... correct me if I'm wrong

Re: [algogeeks] google os ques on pipelining

2011-09-26 Thread gaurav yadav
bharatkumar bagan...can u plz explain why u multipiled (160+5) with 999 ? -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to

[algogeeks] google os ques on pipelining

2011-09-25 Thread siva viknesh
A 4-stage pipeline has the stage delays as 150, 120, 160 and 140 ns (nano seconds) respectively. Registers that are used between the stages have a delay of 5 ns each. Assuming constant clocking rate, the total time taken to process 1000 data items on this pipeline will approximately be a. 120 us