Given an array of size n. It contains numbers in the range 1 to n.
Each number is present at least once except for 2 numbers.
Find the missing numbers.
I know of a solution using another array to store frequency of each
number..
But this holds for than 2 nums also..
So Is there any other solution
sum of n elements from 1=n(n+1)/2
product from 1 to n=n!
calculate dis..
sum=calculated sum-orig sum
prod=calculated prod-orig prod
with dis form quadratic eq and solve...
hope this works...
On Tue, Oct 12, 2010 at 12:29 AM, Asquare anshika.sp...@gmail.com wrote:
Given an array of size n. It