order of evaluation for such expressions is not defined in standard c.it is
compiler dependent./ is not sequence point
On Sat, Sep 3, 2011 at 11:05 PM, vivek goel vivek.thapar2...@gmail.comwrote:
firstly ++i will be evaluatedso i=6
then expression will be
i=6/6;
so now i
code:-
void main()
{
int i=5;
i=(++i)/(i++);
printf(%d,i)
}
Output is 2
plz explain how it is?
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firstly ++i will be evaluatedso i=6
then expression will be
i=6/6;
so now i will be equal to 1..
after the expression will be evaluated
i++ post increment will work
since, post increment works only if a semi-colon occurs or comma operator
occurs.
so now i will increment
its compiler dependent
On Sat, Sep 3, 2011 at 10:59 PM, sinjanspecial sinjanspec...@gmail.comwrote:
code:-
void main()
{
int i=5;
i=(++i)/(i++);
printf(%d,i)
}
Output is 2
plz explain how it is?
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Algorithm
