@ankit: does that mean that after the compiler is informed that the void
pointer will point to integer witht he typecast statement and then we point
it to some other type , it will be an error?
i mean after that typecast statement, if i do
char a;
k=a;is it wrng?
On Tue, Aug 9, 2011 at 2:06
why j and k point different location?
#includestdio.h
main()
{
int a=10,*j;
void *k;
j=k=a;
k=(int *)k;
k++;
j++;
printf(%u %u\n,j,k);
}
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Regards
Rajesh Kumar
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its because void pointer is incremented by 1, when we do k++
whereas integer pointer is incremented by 4, when we do j++
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To
thanx Ankit
On Tue, Aug 9, 2011 at 5:27 PM, ankit sambyal ankitsamb...@gmail.comwrote:
its because void pointer is incremented by 1, when we do k++
whereas integer pointer is incremented by 4, when we do j++
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The typecasting tells the compiler that the void pointer is now pointing to
an integer and when we use this pointer to access the integer it takes value
from 4 bytes. But when we try to increment that pointer, it will point to
the next byte. Try taking k as pointer to double instead of void, u
typecast only temporarily changes the pointer type of LHS but cannot change
that of RHS or even LHS permanently
On Tue, Aug 9, 2011 at 5:36 PM, ankit sambyal ankitsamb...@gmail.comwrote:
The typecasting tells the compiler that the void pointer is now pointing to
an integer and when we use this
I read somewhere that arithmetic operations can't be performed to void
pointers?? How does v++ does'nt giv error??
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