thank you :)
Rahul Rai , 6 Kas 2018 Sal, 14:16 tarihinde şunu
yazdı:
> Let the glass be numbered 0 1 2 3... (2n - 1).
> And the glass numbered 0 1 2 3...(n - 1) are filled.
> Pick every alternating ith filled glass starting from 1 indexed glass and
> swap it with the (n - 1 - i)th unfilled glass
Let the glass be numbered 0 1 2 3... (2n - 1).
And the glass numbered 0 1 2 3...(n - 1) are filled.
Pick every alternating ith filled glass starting from 1 indexed glass and
swap it with the (n - 1 - i)th unfilled glass.
Index 1 will swap with 2n - 2 indexed glass.
Index 3 will swap with 2n - 4 i
