A modification in the above code,
int divide(int a, int b)
{
int temp = 0;
int result = 0;
int mask, i;
printf (a = %d, b = %d\n, a, b);
temp = 0;
for ( i = 30; i = 0; i-- ) {
mask = 1 i;
temp = 1;
Solve it using shift operator here is the crude algo :
the procedure for the division algorithm, given a dividend and a divisor
would be to left shift (multiply by 2) the divisor till it reaches
dividend/2, then continue this routine with the the difference between the
dividend and divisor
thnxx all.. i got the soln..
Qdumanshu: i was asking for quotient and remainder when we divide 2 nos.
without actually dividing them...
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could someone explain the algo with an example?
On Sun, May 22, 2011 at 8:21 PM, Puneet Ginoria punnu.gino...@gmail.comwrote:
thnxx all.. i got the soln..
Qdumanshu: i was asking for quotient and remainder when we divide 2 nos.
without actually dividing them...
--
You received this
a divide b
while(b!=1){
a =1;
b =1;
}
printf(%d\n,a);
Wladimir Araujo Tavares
*Federal University of Ceará
*
On Sun, May 22, 2011 at 1:33 PM, Prakash D IT @ CEG cegprak...@gmail.comwrote:
could someone explain the algo with an example?
On Sun, May 22, 2011 at 8:21 PM, Puneet
try for 15 and 3
On Sun, May 22, 2011 at 10:22 PM, D.N.Vishwakarma@IITR deok...@gmail.comwrote:
a divide b
while(b!=1){
a =1;
b =1;
}
printf(%d\n,a);
On 5/22/11, Wladimir Tavares wladimir...@gmail.com wrote:
a divide b
while(b!=1){
a =1;
b =1;
}
printf(%d\n,a);
Try the following code: One can more optimize it.
int divide(int a, int b)
{
int temp = 0;
int result = 0;
int mask, i;
printf (a = %d, b = %d\n, a, b);
temp = 0;
for ( i = 30; i = 0; i-- ) {
mask = 1 i;
