If a compiler is compiling the code, simply means the compiler is
intelligent enough to know what you want to do. But the language
specifications, clearly explains not to do such things as these are
non-portable!!
Thanks & Regards,
Prashant Bhutani
Senior Undergraduate
Computer Science & Engineeri
If the value can change then do the memory initialization at run-time using
malloc/calloc.
The line 5 is giving error because the declaration of an array (and so the
allocation of memory) happens at compile time, while the initialization of
the variables happen when the program is loaded for the ex
yeah
u can do any non executable statement before you declare the array.remove
clrscr statement everything will be fine
http://www.ideone.com/SpKpQ
On Sat, Jul 30, 2011 at 1:16 PM, Bhanu Pratap Singh wrote:
> In GCC, its okay!!
>
>
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In GCC, its okay!!
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just adding to the concept.. this is not allowed since value of max may
change during the program .. either by declaring it as a macro or as a const
we (as said by ankur and varun ) restrict that the value from changing
during the program ..!!
On Sat, Jul 30, 2011 at 1:09 PM, Ankur Khurana wrote:
or const int max=5;
On Sat, Jul 30, 2011 at 1:09 PM, varun pahwa wrote:
> make max as a macro. as for c static memory allocation take place either
> with a constant or a macro.
> i.e.
> either u declare
> #define max 5
> then write float arr[max];
>
> or u may write
>
> float arr[5];
>
>
>
>
> On
make max as a macro. as for c static memory allocation take place either
with a constant or a macro.
i.e.
either u declare
#define max 5
then write float arr[max];
or u may write
float arr[5];
On Sat, Jul 30, 2011 at 1:05 PM, Arshad Alam wrote:
> Why it is showing an error at line number 5
>
