This question was asked in a Microsoft interview 2 years back.
On Mon, Jun 7, 2010 at 8:05 PM, divya jain wrote:
> let a[n][n] be the input array nd b[][] be the output
>
>
> for(i=0;i for(j=0;j b[i][j]=a[n-j-1][n-i-1]
>
>
>
> On 7 June 2010 08:26, sharad wrote:
>
>> write a c rou
#include
using namespace std;
int main(){
int a[4][4]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16};
int i=0,j,n=3,l=0,m=n;
j=n;
while(i<=n){
int i1=i,j1=j,k=0,l=n;
for(;k wrote:
> write a c routine to flip an nXn matrix about its non major diagnol
>
>
> 3 4
@Sharad,
3 4 5
A= 6 7 9
1 2 8
If B[i,j] = A[n-j, n-i]
then
---
8 9 5
B = 2 7 4
1 6 3
Mohit Ranjan
On Mon, Jun 7, 2010 at 8:26 AM, sharad wrote:
> write a c routine to flip an
let a[n][n] be the input array nd b[][] be the output
for(i=0;i wrote:
> write a c routine to flip an nXn matrix about its non major diagnol
>
>
> 3 4 5
> 6 7 9
> 1 2 8
>
> Transpose is:
> 8 9 5
> 2 7 4
> 1 6 3
>
> --
> You r
