Or this:
if (string1.equals(string2)) {
...
}
String ;^)
On Jun 29, 8:18 pm, Brad Gies rbg...@gmail.com wrote:
use String1.compareTo(String2) == 0
On 29/06/2010 1:53 AM, Martin wrote:
Hi,
I have a strange error that I can't understand. I have this code:
if (VersionsKoll
Further clarification: in Java the == operator works differently for
primitive types (int, double, etc.) than for Objects (such as String).
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Actually, it works the same for both Objects and primitive types.
The == operator checks if the value held by both variables is the
same.
For primitive types (e.g. int), this value is a 32-bit value (or 64-
bit for long, etc).
For Objects, this value is the *reference* to an object, not the
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