I don't understand how #define AST_FORMAT_ADPCM(1 5) becomes
a format = 32 in the * console display.
1 shift left 5 == 2 to the power of 5 = 32.
Mark
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I've been trying to find a list of codec format numbers so I can more
clearly understand the following message;
Accepting AUTHENTICATED call from xxx.xxx.xxx.xxx, requested format = 4,
actual format = 4
I've seen 4, 32, 512 and I think a few others. For example I think format
32 equal ADPCM but
The formats that asterisk uses are #define'd in
asterisk/include/asterisk/frame.h
RTP formats are #define'd in asterisk/rtp.c
regards
Martin
On Fri, 14 Mar 2003, John Vozza wrote:
I've been trying to find a list of codec format numbers so I can more
clearly understand the following message;
Thanks for the feedback but I'm still lost on this one (Forgive my
ignorance please)
I don't understand how #define AST_FORMAT_ADPCM(1 5) becomes
a format = 32 in the * console display.
Regards
John
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NetRom
On Fri, 2003-03-14 at 14:44, John Vozza wrote:
Thanks for the feedback but I'm still lost on this one (Forgive my
ignorance please)
I don't understand how #define AST_FORMAT_ADPCM(1 5) becomes
a format = 32 in the * console display.
1 5
means to shift 1, 5 bits to the left.
Binary mathematics You can think of 15 as 2 to the 5th
power.
10 be 1
11 be 2
12 be 4
13 be 8
14 be 16
15 be 32
Perhaps there might need to be a slightly more friendly message, but
remember its just a debug message.
Jeremy McNamara
John Vozza wrote:
Thanks for the feedback
On Fri, Mar 14, 2003 at 03:44:46PM -0500, John Vozza wrote:
Thanks for the feedback but I'm still lost on this one (Forgive my
ignorance please)
I don't understand how #define AST_FORMAT_ADPCM(1 5) becomes
a format = 32 in the * console display.
2*2*2*2*2 = 32.
Okay, less
