Re: [asterisk-users] Bridge 2 incoming calls

2008-09-08 Thread Russell Bryant
On Sep 5, 2008, at 10:06 AM, Tim Panton wrote: > > On 5 Sep 2008, at 15:50, Steve Murphy wrote: >> Not in 1.4, but in trunk,(and 1.6.x) there is a the Bridge manager >> command you can call via the manager interface, which takes two >> required args, the names of the two channels to bridge, and a

Re: [asterisk-users] Bridge 2 incoming calls

2008-09-05 Thread Tim Panton
On 5 Sep 2008, at 15:50, Steve Murphy wrote: > On Fri, 2008-09-05 at 12:27 +0100, Tim Panton wrote: >> I think I've forgotten something obvious >> >> I've got 2 incoming calls, I want to bridge them - how can I do >> this ? >> >> (assume I somehow know which calls should be paired up...) >>

Re: [asterisk-users] Bridge 2 incoming calls

2008-09-05 Thread Tim Panton
I knew I'd forgotten something. Doh! On 5 Sep 2008, at 14:57, Andreas Brodmann wrote: Tim, you may want to try: 1) Park call 1 2) Pickup call 1 with call 2 (using ParkedCall) Regards, Andreas 2008/9/5 Tim Panton <[EMAIL PROTECTED]> I think I've forgotten something obvious I've got 2 i

Re: [asterisk-users] Bridge 2 incoming calls

2008-09-05 Thread Steve Murphy
On Fri, 2008-09-05 at 12:27 +0100, Tim Panton wrote: > I think I've forgotten something obvious > > I've got 2 incoming calls, I want to bridge them - how can I do this ? > > (assume I somehow know which calls should be paired up...) > > I could dump them both in a meetme - but that seems wa

Re: [asterisk-users] Bridge 2 incoming calls

2008-09-05 Thread Andreas Brodmann
Tim, you may want to try: 1) Park call 1 2) Pickup call 1 with call 2 (using ParkedCall) Regards, Andreas 2008/9/5 Tim Panton <[EMAIL PROTECTED]> > I think I've forgotten something obvious > > I've got 2 incoming calls, I want to bridge them - how can I do this ? > > (assume I somehow kno

[asterisk-users] Bridge 2 incoming calls

2008-09-05 Thread Tim Panton
I think I've forgotten something obvious I've got 2 incoming calls, I want to bridge them - how can I do this ? (assume I somehow know which calls should be paired up...) I could dump them both in a meetme - but that seems wasteful as i _know_ there will only ever be 2 parties. (And I need D