On Sep 5, 2008, at 10:06 AM, Tim Panton wrote:
>
> On 5 Sep 2008, at 15:50, Steve Murphy wrote:
>> Not in 1.4, but in trunk,(and 1.6.x) there is a the Bridge manager
>> command you can call via the manager interface, which takes two
>> required args, the names of the two channels to bridge, and a
On 5 Sep 2008, at 15:50, Steve Murphy wrote:
> On Fri, 2008-09-05 at 12:27 +0100, Tim Panton wrote:
>> I think I've forgotten something obvious
>>
>> I've got 2 incoming calls, I want to bridge them - how can I do
>> this ?
>>
>> (assume I somehow know which calls should be paired up...)
>>
I knew I'd forgotten something.
Doh!
On 5 Sep 2008, at 14:57, Andreas Brodmann wrote:
Tim,
you may want to try:
1) Park call 1
2) Pickup call 1 with call 2 (using ParkedCall)
Regards,
Andreas
2008/9/5 Tim Panton <[EMAIL PROTECTED]>
I think I've forgotten something obvious
I've got 2 i
On Fri, 2008-09-05 at 12:27 +0100, Tim Panton wrote:
> I think I've forgotten something obvious
>
> I've got 2 incoming calls, I want to bridge them - how can I do this ?
>
> (assume I somehow know which calls should be paired up...)
>
> I could dump them both in a meetme - but that seems wa
Tim,
you may want to try:
1) Park call 1
2) Pickup call 1 with call 2 (using ParkedCall)
Regards,
Andreas
2008/9/5 Tim Panton <[EMAIL PROTECTED]>
> I think I've forgotten something obvious
>
> I've got 2 incoming calls, I want to bridge them - how can I do this ?
>
> (assume I somehow kno
I think I've forgotten something obvious
I've got 2 incoming calls, I want to bridge them - how can I do this ?
(assume I somehow know which calls should be paired up...)
I could dump them both in a meetme - but that seems wasteful
as i _know_ there will only ever be 2 parties. (And I need D