Re: [asterisk-users] phpagi problem

Mauricio Mantilla wrote: Yeah, I wrote it on a different file and it worked, i guess there was some hidden character in the script that was messing it up. Thank you anyway, Mauricio Mantilla On 7/17/06, *Time Bandit* <[EMAIL PROTECTED] > wrote: > #!/usr/bin/ph

Re: [asterisk-users] phpagi problem

Yeah, I wrote it on a different file and it worked, i guess there was some hidden character in the script that was messing it up.Thank you anyway,Mauricio MantillaOn 7/17/06, Time Bandit <[EMAIL PROTECTED]> wrote: > #!/usr/bin/php -q>  > require('/var/lib/asterisk/agi-bin/phpagi.php');> $agi = new

Re: [asterisk-users] phpagi problem

#!/usr/bin/php -q say_digits(62410); $cid = $agi->get_variable("dir"); $agi->say_digits($cid); ?> I'm getting this error: parse error, unexpected '=' on line 6 I don't know why you're getting this error, it parse correctly here. But one thing is that the line "$agi->say_digits($cid);" won'

[asterisk-users] phpagi problem

Hi all,I'm trying to write a script using phpagi, but there's something that's not working and I can't figure out why.Here's my code:#!/usr/bin/php -q  phprequire('/var/lib/asterisk/agi-bin/phpagi.php'); $agi = new AGI(); $agi->say_digits(62410); $cid = $agi->get_variable("dir");$agi->say_digits($